
Round off the following numbers to the nearest thousand 9,600.
Answer
410.1k+ views
Hint: According to the question we have to round off to the thousand places of the given number 9,600. So first of all we have to find the one place of the given number and after finding the one place of the given number, we will find the tens place of the given number and again the same way, we will find the hundreds place of the given number. After finding the hundreds place of the given number, we will find the thousands place of the given number. Now as we have obtained all the ones, tens, hundreds and thousands place and if it’s digits at hundreds and tens place are greater than the tens and ones place, we replace each of the thousands, hundreds, tens and ones place digits by 0 and we have to keep the other digits as they are. Hence with the help of this process given above, we can obtain the round off 9600 to thousands place.
Complete step-by-step solution:
According to our question it is asked of us to round off 9,600 to the nearest thousand. As asked in the question, first of all we will find one place in the given number 9,600, which is 0 and it is the same as the tens place of the given number which is 0 and the hundreds place is 6 and thousands place is 9. We have obtained the ones, tens, hundreds, and thousands as 0, 0, 6 and 9. We can see that the digit at the hundreds place is 6, which is greater than 0 and the digit at tens place is 0, which is the same as one's place also. Hence, we have to replace each of the hundreds, tens and ones digits by 0 and keep the remaining digits the same. Now, as given in the question, the number is 9,600 and after rearranging the hundreds, tens and ones digits, the obtained number is 9,000, but the nearest number is 10,000.
So, the nearest thousand is 10,000.
Note:The ones, tens, hundreds, and thousands places which are 0, 0, 6, 9 and 0, we can see its digit at hundreds place is 1, which is less than 5. Hence, we have to replace each of the thousands, hundreds, tens and ones digit by 0 and keep the remaining digits as it is.
Complete step-by-step solution:
According to our question it is asked of us to round off 9,600 to the nearest thousand. As asked in the question, first of all we will find one place in the given number 9,600, which is 0 and it is the same as the tens place of the given number which is 0 and the hundreds place is 6 and thousands place is 9. We have obtained the ones, tens, hundreds, and thousands as 0, 0, 6 and 9. We can see that the digit at the hundreds place is 6, which is greater than 0 and the digit at tens place is 0, which is the same as one's place also. Hence, we have to replace each of the hundreds, tens and ones digits by 0 and keep the remaining digits the same. Now, as given in the question, the number is 9,600 and after rearranging the hundreds, tens and ones digits, the obtained number is 9,000, but the nearest number is 10,000.
So, the nearest thousand is 10,000.
Note:The ones, tens, hundreds, and thousands places which are 0, 0, 6, 9 and 0, we can see its digit at hundreds place is 1, which is less than 5. Hence, we have to replace each of the thousands, hundreds, tens and ones digit by 0 and keep the remaining digits as it is.
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