
Roohi travels 300km to her home partly by train and partly by bus. She takes 4 hours if she travels 60km by train and the remaining by bus. If she travels 100km by train and the remaining by bus, she takes 10 minutes longer. Find the speed of the train and the bus separately.
Answer
612.6k+ views
Hint- This question can be solved by converting the given statements into linear equations.
Given that, Roohi has to travel a total distance = 300km
And she has to travel partly by bus and partly by train.
Let the speed of the train and bus be $u{\text{ }}km{\text{ per }}h$ and $v{\text{ }}km{\text{ per }}h$ respectively.
According to the question,
She takes $4$ hours if she travels $60km$ by train and the remaining by bus.
Now distance travelled by train$ = 60km$
Distance travelled by bus$ = 240km$
Or $\dfrac{{60}}{u} + \dfrac{{240}}{v} = 4 - - - - - - - - \left( i \right)$
Also it is given that,
If she travels $100km$ by train and the remaining by bus, she takes $10$ minutes longer.
Now distance travelled by train$ = 100km$
Distance travelled by bus$ = 200km$
Or $
\dfrac{{100}}{u} + \dfrac{{200}}{v} = 4 + \dfrac{{10}}{{60}} \\
\dfrac{{100}}{u} + \dfrac{{200}}{v} = \dfrac{{25}}{6} - - - - - - - - \left( {ii} \right) \\
$
Let $\dfrac{1}{u} = p$ and $\dfrac{1}{v} = q$
Thus the given equation reduces to
$
60p + 240q = 4 - - - - - - \left( {iii} \right) \\
100p + 200q = \dfrac{{25}}{6} \\
600p + 1200q = 25 - - - - - - \left( {iv} \right) \\
$
Multiplying $\left( {iii} \right)$ by $10$ we get,
$600p + 2400q = 40 - - - - - - \left( v \right)$
Subtracting $\left( {v} \right)$ from $\left( iv \right)$ we get,
$
600p + 2400q-600p - 1200q=40-25 \\
1200q = 15 \\
q = \dfrac{{15}}{{1200}} \\
q = \dfrac{1}{{80}} \\
$
Substituting the value of $q$ in $\left( {iii} \right)$ we get,
$
60p + 3 = 4 \\
60p = 1 \\
p = \dfrac{1}{{60}} \\
\therefore p = \dfrac{1}{u} = \dfrac{1}{{60}},q = \dfrac{1}{v} = \dfrac{1}{{80}} \\
$
Or $u = 60km{\text{ per }}h{\text{ }},{\text{ }}v = 80km{\text{ per }}h$
Thus the speed of the train and the speed of the bus are $60{\text{ }}km{\text{ per }}h$ and $80{\text{ }}km{\text{ per }}h$ respectively.
Note- Whenever we face such types of questions the key concept is that we should mention what is given to us and assume some variables which we need to find and then convert the statements into linear equations like we did and solve the equations to get our desired answer.
Given that, Roohi has to travel a total distance = 300km
And she has to travel partly by bus and partly by train.
Let the speed of the train and bus be $u{\text{ }}km{\text{ per }}h$ and $v{\text{ }}km{\text{ per }}h$ respectively.
According to the question,
She takes $4$ hours if she travels $60km$ by train and the remaining by bus.
Now distance travelled by train$ = 60km$
Distance travelled by bus$ = 240km$
Or $\dfrac{{60}}{u} + \dfrac{{240}}{v} = 4 - - - - - - - - \left( i \right)$
Also it is given that,
If she travels $100km$ by train and the remaining by bus, she takes $10$ minutes longer.
Now distance travelled by train$ = 100km$
Distance travelled by bus$ = 200km$
Or $
\dfrac{{100}}{u} + \dfrac{{200}}{v} = 4 + \dfrac{{10}}{{60}} \\
\dfrac{{100}}{u} + \dfrac{{200}}{v} = \dfrac{{25}}{6} - - - - - - - - \left( {ii} \right) \\
$
Let $\dfrac{1}{u} = p$ and $\dfrac{1}{v} = q$
Thus the given equation reduces to
$
60p + 240q = 4 - - - - - - \left( {iii} \right) \\
100p + 200q = \dfrac{{25}}{6} \\
600p + 1200q = 25 - - - - - - \left( {iv} \right) \\
$
Multiplying $\left( {iii} \right)$ by $10$ we get,
$600p + 2400q = 40 - - - - - - \left( v \right)$
Subtracting $\left( {v} \right)$ from $\left( iv \right)$ we get,
$
600p + 2400q-600p - 1200q=40-25 \\
1200q = 15 \\
q = \dfrac{{15}}{{1200}} \\
q = \dfrac{1}{{80}} \\
$
Substituting the value of $q$ in $\left( {iii} \right)$ we get,
$
60p + 3 = 4 \\
60p = 1 \\
p = \dfrac{1}{{60}} \\
\therefore p = \dfrac{1}{u} = \dfrac{1}{{60}},q = \dfrac{1}{v} = \dfrac{1}{{80}} \\
$
Or $u = 60km{\text{ per }}h{\text{ }},{\text{ }}v = 80km{\text{ per }}h$
Thus the speed of the train and the speed of the bus are $60{\text{ }}km{\text{ per }}h$ and $80{\text{ }}km{\text{ per }}h$ respectively.
Note- Whenever we face such types of questions the key concept is that we should mention what is given to us and assume some variables which we need to find and then convert the statements into linear equations like we did and solve the equations to get our desired answer.
Recently Updated Pages
What happens to glucose which enters nephron along class 10 biology CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

When the JanmiKudian Act was passed that granted the class 10 social science CBSE

A sector containing an angle of 120 circ is cut off class 10 maths CBSE

The sum of digits of a two digit number is 13 If t-class-10-maths-ICSE

Trending doubts
The shortest day of the year in India

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

What is the missing number in the sequence 259142027 class 10 maths CBSE

