# Prove that the sum of all angles of a triangle is $180^\circ $

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In this question we have to use construction and use the properties of parallel lines . Use substitution of angles of the triangle with the angles on the straight line to get to the final answer .

Complete step-by-step answer:

Construct a straight line EF passing through A parallel to the base BC of the triangle .

$\angle ABC = \angle EAB$ ( alternate angles are equal as lines BC and EF are parallel )

$\angle BCA = \angle FAC$ ( alternate angles )

Now we know that the sum of all linear angles is $180^\circ $

Therefore $\angle EAB + \angle BAC + \angle FAC = 180^\circ $

By substitution of angles from above , we get

$\angle ABC + \angle CAB + \angle ACB = 180^\circ $

Hence proved the sum of all angles of a triangle is $180^\circ $

Note –In such questions construction becomes necessary to prove the desired result. We should remember the properties of parallel lines to get the desired answer .

Complete step-by-step answer:

Construct a straight line EF passing through A parallel to the base BC of the triangle .

$\angle ABC = \angle EAB$ ( alternate angles are equal as lines BC and EF are parallel )

$\angle BCA = \angle FAC$ ( alternate angles )

Now we know that the sum of all linear angles is $180^\circ $

Therefore $\angle EAB + \angle BAC + \angle FAC = 180^\circ $

By substitution of angles from above , we get

$\angle ABC + \angle CAB + \angle ACB = 180^\circ $

Hence proved the sum of all angles of a triangle is $180^\circ $

Note –In such questions construction becomes necessary to prove the desired result. We should remember the properties of parallel lines to get the desired answer .

Last updated date: 24th Sep 2023

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