How many multiples of 4 lie in between 10 and 250?
(a) 60
(b) 70
(c) 80
(d) 90
Answer
Verified
504.6k+ views
Hint: To solve this question, we need to know the basic concepts of arithmetic progression. Here, the first term of the given arithmetic progression is the smallest integer greater than 10 which is a multiple of 4, while the last term would be the largest integer just smaller than 250 which is a multiple of 4. We need to form an arithmetic progression with a common difference as 4. The formula of the ${{n}^{th}}$ term of this series is given by -
${{a}_{n}}$= a + (n-1) d
${{a}_{n}}$= ${{n}^{th}}$ term of this series
a = first term of the series
n = number of terms in the series
d= common difference (4 in this case)
The value of n will give the required answer.
Complete step-by-step solution -
Since, we need to find the arithmetic progression to solve the problem, we first find the first term of the arithmetic progression. Thus, we first start by finding the smallest integer greater than 10 which is a multiple of 4. This is clearly 12 (since, 11 is not multiple of 4 and thus 12 would be the required number). Now, we find the last term. For this we start with 249 (largest number just smaller than 250). Since, this is not a multiple of 4, we then move onto 248. This is in fact a multiple of 4, thus we have found our last term. Since, we have to find the multiple of 4, the common difference is 4. Thus, we have in the equation ${{a}_{n}}$= a + (n-1) d, we have,
${{a}_{n}}$ = 248
a = 12
d = 4
Now, substituting the values, we have,
248 = 12 + 4 (n-1)
(n-1) = $\dfrac{248-12}{4}$
(n-1) = 59
n = 60
Thus, the number of multiples of 4 that lie in between 10 and 250 are 60.
Note: Another way to find the answer between two numbers (say a and b) is by doing the following. We first find the remainder when we divide 250 by 4 (which is 2). We then subtract 2 from 250 to get the last term (250 – 2 = 248) of the arithmetic progression. We then find the remainder when we divide 10 by 4 (which is 2). We then add 2 to 10 (which is 10 + 2=12) to get the first term. Now, we find the answer by using the formula –
$\dfrac{248}{4}-\dfrac{12}{4}+1$ = 62 – 3 + 1 = 60 (which is the same answer as the one in the solutions.)
${{a}_{n}}$= a + (n-1) d
${{a}_{n}}$= ${{n}^{th}}$ term of this series
a = first term of the series
n = number of terms in the series
d= common difference (4 in this case)
The value of n will give the required answer.
Complete step-by-step solution -
Since, we need to find the arithmetic progression to solve the problem, we first find the first term of the arithmetic progression. Thus, we first start by finding the smallest integer greater than 10 which is a multiple of 4. This is clearly 12 (since, 11 is not multiple of 4 and thus 12 would be the required number). Now, we find the last term. For this we start with 249 (largest number just smaller than 250). Since, this is not a multiple of 4, we then move onto 248. This is in fact a multiple of 4, thus we have found our last term. Since, we have to find the multiple of 4, the common difference is 4. Thus, we have in the equation ${{a}_{n}}$= a + (n-1) d, we have,
${{a}_{n}}$ = 248
a = 12
d = 4
Now, substituting the values, we have,
248 = 12 + 4 (n-1)
(n-1) = $\dfrac{248-12}{4}$
(n-1) = 59
n = 60
Thus, the number of multiples of 4 that lie in between 10 and 250 are 60.
Note: Another way to find the answer between two numbers (say a and b) is by doing the following. We first find the remainder when we divide 250 by 4 (which is 2). We then subtract 2 from 250 to get the last term (250 – 2 = 248) of the arithmetic progression. We then find the remainder when we divide 10 by 4 (which is 2). We then add 2 to 10 (which is 10 + 2=12) to get the first term. Now, we find the answer by using the formula –
$\dfrac{248}{4}-\dfrac{12}{4}+1$ = 62 – 3 + 1 = 60 (which is the same answer as the one in the solutions.)
Recently Updated Pages
If the perimeter of the equilateral triangle is 18-class-10-maths-CBSE
How do you make the plural form of most of the words class 10 english CBSE
Quotes and Slogans on Consumer Rights Can Anybody Give Me
What is the orbit of a satellite Find out the basis class 10 physics CBSE
the period from 1919 to 1947 forms an important phase class 10 social science CBSE
If the average marks of three batches of 55 60 and class 10 maths CBSE
Trending doubts
Imagine that you have the opportunity to interview class 10 english CBSE
Find the area of the minor segment of a circle of radius class 10 maths CBSE
Fill the blanks with proper collective nouns 1 A of class 10 english CBSE
Frogs can live both on land and in water name the adaptations class 10 biology CBSE
Fill in the blank One of the students absent yesterday class 10 english CBSE
Write a letter to the Principal of your school requesting class 10 english CBSE