Answer

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Hint: The question is related to the linear equation in two variables. Try to make two equations using the information given in the problem statement and solve them simultaneously.

Complete step-by-step answer:

Complete step-by-step answer: In the question, it is given that Meena withdrew \[Rs.2000\] from a bank in the form of notes of $Rs.50$ and $Rs.100$. It is also given that she got $25$ notes in all. So, we will consider $x$ as the number of $Rs.50$ notes received by Meena and $y$ as the number of $Rs.100$ notes received by Meena.

Now, in the first case, it is given that Meena withdrew \[Rs.2000\] from a bank in the form of notes of $Rs.50$ and $Rs.100$. So, the amount in the form of $Rs.50$ notes is equal to $50\times x=Rs.50x$. Also, the amount in the form of $Rs.100$ notes is equal to $100\times y=Rs.100y$. So, the total amount will be $Rs.\left( 50x+100y \right)$. But it is given that the total amount withdrawn is \[Rs.2000\]. So,

$50x+100y=2000..........(i)$

Now, we have considered $x$ as the number of $Rs.50$ notes received by Meena and $y$ as the number of $Rs.100$ notes received by Meena. So, the total number of notes will be equal to $x+y$. But it is given that the total number of notes is equal to $25$. So,

$x+y=25.....(ii)$

Now, we will solve the linear equations to find the values of $x$ and $y$.

From equation$(ii)$, we have $x+y=25$

$\Rightarrow y=25-x$

On substituting $y=25-x$ in equation$(i)$, we get

$50x+100\left( 25-x \right)=2000$

$\Rightarrow 50x+2500-100x=2000$

$\Rightarrow 500-50x=0$

$\Rightarrow 50x=500$

$\Rightarrow x=10$

Now, substituting \[x=10\] in equation$(ii)$, we get

$10+y=25$

\[\Rightarrow y=15\]

Hence, the numbers of $Rs.50$ notes and \[Rs.100\] notes that are received by Meena from the cashier are $10$ and $15$ respectively.

Note: While solving this question we can assume the number of RS.50 notes as x and RS.100 notes as (25-x). By this substitution we get a linear equation in one variable. We can find the value of x by solving the linear equation in one variable.

Complete step-by-step answer:

Complete step-by-step answer: In the question, it is given that Meena withdrew \[Rs.2000\] from a bank in the form of notes of $Rs.50$ and $Rs.100$. It is also given that she got $25$ notes in all. So, we will consider $x$ as the number of $Rs.50$ notes received by Meena and $y$ as the number of $Rs.100$ notes received by Meena.

Now, in the first case, it is given that Meena withdrew \[Rs.2000\] from a bank in the form of notes of $Rs.50$ and $Rs.100$. So, the amount in the form of $Rs.50$ notes is equal to $50\times x=Rs.50x$. Also, the amount in the form of $Rs.100$ notes is equal to $100\times y=Rs.100y$. So, the total amount will be $Rs.\left( 50x+100y \right)$. But it is given that the total amount withdrawn is \[Rs.2000\]. So,

$50x+100y=2000..........(i)$

Now, we have considered $x$ as the number of $Rs.50$ notes received by Meena and $y$ as the number of $Rs.100$ notes received by Meena. So, the total number of notes will be equal to $x+y$. But it is given that the total number of notes is equal to $25$. So,

$x+y=25.....(ii)$

Now, we will solve the linear equations to find the values of $x$ and $y$.

From equation$(ii)$, we have $x+y=25$

$\Rightarrow y=25-x$

On substituting $y=25-x$ in equation$(i)$, we get

$50x+100\left( 25-x \right)=2000$

$\Rightarrow 50x+2500-100x=2000$

$\Rightarrow 500-50x=0$

$\Rightarrow 50x=500$

$\Rightarrow x=10$

Now, substituting \[x=10\] in equation$(ii)$, we get

$10+y=25$

\[\Rightarrow y=15\]

Hence, the numbers of $Rs.50$ notes and \[Rs.100\] notes that are received by Meena from the cashier are $10$ and $15$ respectively.

Note: While solving this question we can assume the number of RS.50 notes as x and RS.100 notes as (25-x). By this substitution we get a linear equation in one variable. We can find the value of x by solving the linear equation in one variable.

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