Answer
Verified
424.5k+ views
Hint: Take any general element of \[{{R}_{0}}\] and find the identity element of \[R\] by forming the equations using properties of the identity element and then solve them. Similarly take any general element of \[R\] and find the identity of \[{{R}_{0}}\] by forming equations using properties of the identity element.
Complete step-by-step answer:
We have the set \[A={{R}_{0}}\times R\] where \[{{R}_{0}}\] denotes the set of all non-zero numbers. We have a binary relation on \[A\] defined as \[\left( a,b \right)O\left( c,d \right)=\left( ac,bc+d \right)\] for all \[\left( a,b \right),\left( c,d \right)\in {{R}_{0}}\times R\]. We have to find the identity element in \[A\].
Let’s assume that the identity element of \[A\] is of the form \[\left( x,y \right)\].
We know that any identity element has the property that any element operated with identity element returns the element itself, i.e., for any \[\left( a,b \right)\in A\], we have \[\left( a,b \right)O\left( x,y \right)=\left( x,y \right)O\left( a,b \right)=\left( a,b \right)\].
We know that for all \[\left( a,b \right),\left( c,d \right)\in {{R}_{0}}\times R\], we have \[\left( a,b \right)O\left( c,d \right)=\left( ac,bc+d \right)\].
Thus, we have \[\left( a,b \right)O\left( x,y \right)=\left( ax,bx+y \right)=\left( a,b \right)\].
Comparing the terms on both sides of the equation, we have \[ax=a,bx+y=b\].
We can clearly see that the solution of the above equations is \[x=1,y=0\].
Hence, we have \[\left( x,y \right)=\left( 1,0 \right)\] as the identity of the given set \[A={{R}_{0}}\times R\] where \[{{R}_{0}}\] denotes the set of all non-zero numbers .
Note: A binary operation is a calculation that combines two elements of a non empty set to produce another element. A binary operation on a non empty set is an operation whose two domains and co-domains are the same set. Addition, subtraction and multiplication are the common binary operations. As the result of performing an operation on a set lies in the set itself, we say that the given binary operation is closed. Binary operations may or may not be associative and distributive. The inverse of any element of a set under binary operation is the element such that the element operated with its inverse gives the identity element.
Complete step-by-step answer:
We have the set \[A={{R}_{0}}\times R\] where \[{{R}_{0}}\] denotes the set of all non-zero numbers. We have a binary relation on \[A\] defined as \[\left( a,b \right)O\left( c,d \right)=\left( ac,bc+d \right)\] for all \[\left( a,b \right),\left( c,d \right)\in {{R}_{0}}\times R\]. We have to find the identity element in \[A\].
Let’s assume that the identity element of \[A\] is of the form \[\left( x,y \right)\].
We know that any identity element has the property that any element operated with identity element returns the element itself, i.e., for any \[\left( a,b \right)\in A\], we have \[\left( a,b \right)O\left( x,y \right)=\left( x,y \right)O\left( a,b \right)=\left( a,b \right)\].
We know that for all \[\left( a,b \right),\left( c,d \right)\in {{R}_{0}}\times R\], we have \[\left( a,b \right)O\left( c,d \right)=\left( ac,bc+d \right)\].
Thus, we have \[\left( a,b \right)O\left( x,y \right)=\left( ax,bx+y \right)=\left( a,b \right)\].
Comparing the terms on both sides of the equation, we have \[ax=a,bx+y=b\].
We can clearly see that the solution of the above equations is \[x=1,y=0\].
Hence, we have \[\left( x,y \right)=\left( 1,0 \right)\] as the identity of the given set \[A={{R}_{0}}\times R\] where \[{{R}_{0}}\] denotes the set of all non-zero numbers .
Note: A binary operation is a calculation that combines two elements of a non empty set to produce another element. A binary operation on a non empty set is an operation whose two domains and co-domains are the same set. Addition, subtraction and multiplication are the common binary operations. As the result of performing an operation on a set lies in the set itself, we say that the given binary operation is closed. Binary operations may or may not be associative and distributive. The inverse of any element of a set under binary operation is the element such that the element operated with its inverse gives the identity element.
Recently Updated Pages
The branch of science which deals with nature and natural class 10 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Define absolute refractive index of a medium
Find out what do the algal bloom and redtides sign class 10 biology CBSE
Prove that the function fleft x right xn is continuous class 12 maths CBSE
Find the values of other five trigonometric functions class 10 maths CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Two charges are placed at a certain distance apart class 12 physics CBSE
Difference Between Plant Cell and Animal Cell
What organs are located on the left side of your body class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
The planet nearest to earth is A Mercury B Venus C class 6 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
What is BLO What is the full form of BLO class 8 social science CBSE