Answer
425.4k+ views
Hint: We will use the fact that gain is equal to selling price minus cost price, i.e. gain= S.P -C.P. To solve this question we will use the formula, $gain\%=\dfrac{gain}{C.P}\times 100$ to get the gain%. Also, the formula for calculating the discount % that is, \[discount\%=\dfrac{discount}{M.P}\times 100\]
(Where M.P. is the marked price of an article). And also the formula, Discount=M.P.-S.P.
Complete step by step answer:
Let the marked price of the suit be x.
Now, using the formula for finding the discount %, we can write the following
\[\begin{align}
& \Rightarrow discount\%=\dfrac{discount}{M.P}\times 100 \\
& \Rightarrow 12.5=\dfrac{discount}{x}\times 100 \\
& \Rightarrow discount=\dfrac{x}{8} \\
\end{align}\]
Now, for finding the selling price of the suit, we can write and use the following formula which is
\[\begin{align}
& \Rightarrow Discount=M.P.-S.P. \\
& \Rightarrow \dfrac{x}{8}=x-S.P. \\
& \Rightarrow \dfrac{7x}{8}=S.P. \\
\end{align}\]
Now, as we know the gain as well as the the gain%, we can write the following
$\begin{align}
& \Rightarrow gain\%=\dfrac{gain}{C.P}\times 100 \\
& \Rightarrow 10=\dfrac{gain}{1470}\times 100 \\
& \Rightarrow Gain=Rs.147 \\
\end{align}$
Now, again, as we know the gain as well as the S.P., we can write the following
\[\begin{align}
& \Rightarrow S.P.-C.P.=gain \\
& \Rightarrow \dfrac{7x}{8}-1470=147 \\
& \Rightarrow \dfrac{7x}{8}=1617 \\
& \Rightarrow x=Rs.1848 \\
\end{align}\]
Hence, the marked price of the suit comes out to be Rs. 1848.
Note: In this question, it is very important to know all the formulas beforehand and also, the calculations should also be done very carefully as there are very high chances that the students might commit a mistake while solving the question and get a wrong solution. Some students may make mistakes and write SP instead of CP in the formula of gain percentage, so the students must remember all the formulas correctly in order to avoid any errors.
(Where M.P. is the marked price of an article). And also the formula, Discount=M.P.-S.P.
Complete step by step answer:
Let the marked price of the suit be x.
Now, using the formula for finding the discount %, we can write the following
\[\begin{align}
& \Rightarrow discount\%=\dfrac{discount}{M.P}\times 100 \\
& \Rightarrow 12.5=\dfrac{discount}{x}\times 100 \\
& \Rightarrow discount=\dfrac{x}{8} \\
\end{align}\]
Now, for finding the selling price of the suit, we can write and use the following formula which is
\[\begin{align}
& \Rightarrow Discount=M.P.-S.P. \\
& \Rightarrow \dfrac{x}{8}=x-S.P. \\
& \Rightarrow \dfrac{7x}{8}=S.P. \\
\end{align}\]
Now, as we know the gain as well as the the gain%, we can write the following
$\begin{align}
& \Rightarrow gain\%=\dfrac{gain}{C.P}\times 100 \\
& \Rightarrow 10=\dfrac{gain}{1470}\times 100 \\
& \Rightarrow Gain=Rs.147 \\
\end{align}$
Now, again, as we know the gain as well as the S.P., we can write the following
\[\begin{align}
& \Rightarrow S.P.-C.P.=gain \\
& \Rightarrow \dfrac{7x}{8}-1470=147 \\
& \Rightarrow \dfrac{7x}{8}=1617 \\
& \Rightarrow x=Rs.1848 \\
\end{align}\]
Hence, the marked price of the suit comes out to be Rs. 1848.
Note: In this question, it is very important to know all the formulas beforehand and also, the calculations should also be done very carefully as there are very high chances that the students might commit a mistake while solving the question and get a wrong solution. Some students may make mistakes and write SP instead of CP in the formula of gain percentage, so the students must remember all the formulas correctly in order to avoid any errors.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)