In the given figure, $DL$ and $BM $are heights on sides $AB$ and $AD$ respectively of parallelogram $ABCD$. If the area of the parallelogram is $1470c{m^2},AB = 35cm$ and $AD = 49cm$, find the length of $BM$and $DL$.
Answer
Verified
Hint: Use formula, Area of parallelogram $ = $base $ \times $ height.
Given, the area of parallelogram is $1470c{m^2}$and $AB = 35cm$ and $AD = 49cm$ are bases of the parallelogram. $DL$ and $BM$ are the corresponding heights of the parallelogram. We know that, Area of parallelogram $ = $base $ \times $ height. Using this formula for finding $DL$: $ \Rightarrow 1470 = AB \times DL, \\ \Rightarrow 1470 = 35 \times DL, \\ \Rightarrow DL = 42. \\ $ Similarly for $BM$: $ \Rightarrow 1470 = AD \times BM, \\ \Rightarrow 1470 = 49 \times BM, \\ \Rightarrow BM = 30. \\ $ Therefore, the lengths of $DL$ and $BM$ are $42cm$ and $30cm$ respectively. Note: There is another formula of area of parallelogram as: Area of parallelogram $ = \frac{1}{2} \times $(product of diagonals). We can use either formulae wherever required, as per our convenience.
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