Answer
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Hint: Use formula, Area of parallelogram $ = $base $ \times $ height.
Given, the area of parallelogram is $1470c{m^2}$and $AB = 35cm$ and $AD = 49cm$ are bases of the parallelogram.
$DL$ and $BM$ are the corresponding heights of the parallelogram.
We know that, Area of parallelogram $ = $base $ \times $ height. Using this formula for finding $DL$:
$
\Rightarrow 1470 = AB \times DL, \\
\Rightarrow 1470 = 35 \times DL, \\
\Rightarrow DL = 42. \\
$
Similarly for $BM$:
$
\Rightarrow 1470 = AD \times BM, \\
\Rightarrow 1470 = 49 \times BM, \\
\Rightarrow BM = 30. \\
$
Therefore, the lengths of $DL$ and $BM$ are $42cm$ and $30cm$ respectively.
Note: There is another formula of area of parallelogram as:
Area of parallelogram $ = \frac{1}{2} \times $(product of diagonals).
We can use either formulae wherever required, as per our convenience.
Given, the area of parallelogram is $1470c{m^2}$and $AB = 35cm$ and $AD = 49cm$ are bases of the parallelogram.
$DL$ and $BM$ are the corresponding heights of the parallelogram.
We know that, Area of parallelogram $ = $base $ \times $ height. Using this formula for finding $DL$:
$
\Rightarrow 1470 = AB \times DL, \\
\Rightarrow 1470 = 35 \times DL, \\
\Rightarrow DL = 42. \\
$
Similarly for $BM$:
$
\Rightarrow 1470 = AD \times BM, \\
\Rightarrow 1470 = 49 \times BM, \\
\Rightarrow BM = 30. \\
$
Therefore, the lengths of $DL$ and $BM$ are $42cm$ and $30cm$ respectively.
Note: There is another formula of area of parallelogram as:
Area of parallelogram $ = \frac{1}{2} \times $(product of diagonals).
We can use either formulae wherever required, as per our convenience.
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