Question

In the following reactions, what will be A, B and C respectively?

A. Plaster of Paris, dead burnt plaster, calcium sulphide
B. dead burnt plaster, plaster of Paris, lime
C. Plaster of Paris, dead burnt plaster, lime
D. Anhydrous calcium sulphate, Plaster of Paris, calcium sulfite

Answer 1

Hint: When calcium sulphate dihydrate is heated at low temperature, some amount of water escapes from the calcium sulphate. On increasing temperature, complete water escapes from calcium sulphate dihydrate. When anhydrous calcium sulphate is strongly heated it converts into an oxide of calcium.

Complete Step by step answer:When calcium sulphate dihydrate is heated at ${\text{120}}{\,^{\text{o}}}{\text{C}}$ , some amount of water escapes from the calcium sulphate.
The reaction is as follows:
\[{\text{CaS}}{{\text{O}}_{\text{4}}}{\text{.2}}{{\text{H}}_{\text{2}}}{\text{O}}\,\mathop \to \limits^{{\text{120}}{\,^{\text{o}}}{\text{C}}} \,\mathop {{\text{CaS}}{{\text{O}}_{\text{4}}}\,.\dfrac{1}{2}{{\text{H}}_{\text{2}}}{\text{O}}}\limits_{\text{A}} + \dfrac{3}{2}{{\text{H}}_{\text{2}}}{\text{O}}\]
The calcium sulphate having half water molecule \[\left( {{\text{CaS}}{{\text{O}}_{\text{4}}}\,.\dfrac{1}{2}{{\text{H}}_{\text{2}}}{\text{O}}} \right)\]is known as Plaster of Paris.
When calcium sulphate dihydrate is heated at ${\text{200}}{\,^{\text{o}}}{\text{C}}$ , complete water escapes from the calcium sulphate.
The reaction is as follows:
\[{\text{CaS}}{{\text{O}}_{\text{4}}}{\text{.2}}{{\text{H}}_{\text{2}}}{\text{O}}\,\mathop \to \limits^{{\text{200}}{\,^{\text{o}}}{\text{C}}} \mathop {\,{\text{CaS}}{{\text{O}}_{\text{4}}}\,}\limits_{\text{B}} + 2\,{{\text{H}}_{\text{2}}}{\text{O}}\]
The anhydrous calcium sulphate\[\left( {{\text{CaS}}{{\text{O}}_{\text{4}}}} \right)\] is known as dead burnt plaster.
When anhydrous calcium sulphate is heated strongly, it dissociates into calcium oxide and sulphur trioxide.
The reaction is as the temperature of the heating is important. At low temperature, some amount of water remains in compound calcium sulphate which is known as Plaster of Paris whereas at high temperature all the water removes which forms the same compound but have different properties.follows:
\[{\text{2}}\,{\text{CaS}}{{\text{O}}_{\text{4}}}\,\mathop \to \limits^{{\text{Strongly}}\,{\text{heated}}} \mathop {\,2\,{\text{CaO}}\,}\limits_{\text{C}} + 2\,{\text{S}}{{\text{O}}_3}\]
The calcium oxide\[\left( {{\text{CaO}}} \right)\] is known as lime.
So, product A is Plaster of Paris, product B is dead burnt plaster and product C is lime.
The calcium sulphide does not form during any reaction, so option (A) is incorrect.
The products are not arranged in the correct order so, option (B) is incorrect.
The products are arranged in the correct order so, option (C) is correct.
The calcium sulphite does not form during any reaction, so option (D) is incorrect.

Therefore, option (C) Plaster of Paris, dead burnt plaster, lime, is correct.

Note: The temperature of the heating is important. At low temperature, some amount of water remains in compound calcium sulphate which is known as Plaster of Paris whereas at high temperature all the water removes which forms the same compound but have different properties.