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**Hint:**From the given geometry diagram we have to find the angle value of $x$. For that, we are going to use the given geometrical relation in the exterior angle of a triangle. To solve this question we have to apply the formula of exterior angles of a triangle and then we need to apply the concept that the sum of all angles of a rectangle is ${360^ \circ }$

**Complete step-by-step answer:**

It is given in the question that $\angle DFZ = {25^ \circ }$

From the diagram we can say that $DZ \bot BF$

Therefore, $\angle DZF = {90^ \circ }$

Now by applying the concept of exterior angles of a triangle we get-

$\angle FDC = \angle DZF + \angle DFZ$$ = {90^ \circ } + {25^ \circ } = {115^ \circ }$

Further it is stated in the question that $\angle KBZ = {35^ \circ }$

Since $DZ \bot BF$ therefore we can write $\angle BZD = {90^ \circ }$

Again, $KD \bot BC$so $\angle BKD = {90^ \circ }$

Now by applying the concept that the sum of all the angles of a rectangle is ${360^ \circ }$ we get-

$\angle KDZ = {360^0} - [\angle BKD + \angle BZD + \angle KBZ] = {360^ \circ } - ({90^ \circ } + {90^ \circ } + {35^ \circ }) = {145^ \circ }$

Since $\angle ZDC$ is a straight angle so $\angle ZDC = {180^ \circ }$

Therefore $\angle KDC = {180^ \circ } - \angle KDZ = {180^ \circ } - {145^ \circ } = {35^ \circ }$

So the value of $x = \angle FDC + \angle KDC - \angle KDE$

Since we know that $KD \bot DE$ therefore $\angle KDE = {90^ \circ }$

Thus $x = {115^ \circ } + {35^ \circ } - {90^ \circ } = {60^ \circ }$

Hence we get the value of $x = {60^ \circ }$

**So the correct option is $C$**

**Note:**A triangle can be considered as a polygon which consists of three sides, three edges, three vertices and the sum of internal angles of a triangle equal to \[180^\circ \].

The sum of all the angles of a triangle (of all types) is equal to \[180^\circ \].

The sum of the length of the two sides of a triangle is always greater than the third side.

The side opposite to the greater angle is the longest side among all the sides of a triangle.

The exterior angle of a triangle is always equal to the sum of the interior opposite angles. This property of a triangle is called an exterior angle property.

Two triangles will be treated as similar if the corresponding angles of both triangles are congruent and lengths of their sides are proportional.

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