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In quadrilateral PQRS , $\angle R={60^\circ}$. Find the ratio of $\angle R$ to $\angle Q$.

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Hint: PQRS is a quadrilateral. The property of quadrilateral says that the sum of any two angles is 180 . All the internal angles of a quadrilateral sum up to ${360^ \circ }$. In this question first we have to find the value of angle Q then we simply can't get the ratio of angle R and angle Q.

Complete step-by-step answer:
We known that \[\angle R + \angle Q = {180^ \circ }\]
And we have the value of angle R is given $\angle R = {60^ \circ }$
Simply put the value of angle R
= ${60^ \circ } + \angle Q = {180^ \circ }$
= $\angle Q = {180^ \circ } - {60^ \circ }$
= $\angle Q = {120^ \circ }$
Now we have the value of angle Q
We can easily find the ratio of angle R and angle Q
For finding the ratio just do $\dfrac{{\angle R}}{{\angle Q}}$
= $\dfrac{{\angle R}}{{\angle Q}}$$ = \dfrac{{60}}{{120}}$
By canceling the denominator and numerator we get
= $\dfrac{{\angle R}}{{\angle Q}}$$ = \dfrac{1}{2}$
Here we get ratio of angle R and angle Q is 1:2

Note: Quadrilateral just means “four side”. A quadrilateral has four sides, it has two dimensional, closed and has straight sides. All the internal angles of a quadrilateral sum up to ${360^ \circ }$. And the most important point is opposite angles are equal and opposite sides are equal and parallel. In quadrilateral sum of any two adjuacent angles is $180$. In quadrilateral if one angle is the right angle then all the angles are the right angle and the diagonals of a parallelogram bisect each other. According to the angle sum property of a quadrilateral, the sum of all the four interior angles is equal to ${360^ \circ }$.