Answer

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**Hint:**We know that the total probability is always $1$ so we can write it as the form of addition, $P$(Winning of Geeta ), and $P$ (Winning of Ritu) is equal to $1$.

When we subtract $P$ (Winning of Ritu) from $1$ to get the required answer.

**Complete step by step answer:**

It is given that the winning of Geeta is a complementary event to winning of Ritu

That is $P$ (winning of Ritu )$ = 0.73$

Here we need to find the probability of winning Geeta.

Thus, we know the concept of the total probability

Therefore, we can say that

$P$ (Winning of Ritu)$ + $P(Winning of Geeta)$ = 1$

Now we have to find the probability of winning Geeta.

So we can write it as,

$\Rightarrow P$ (winning of Geeta) =$1 - $P (Winning of Ritu)

By substituting the value of the probability of the winning of Ritu and we get,

$\Rightarrow P$ (winning of Geeta)$ = $$1 - 0.73$

On subtracting the probability of winning Ritu from $1$

$\Rightarrow $ Probability of Winning Geeta $ = 0.27$

**Therefore, the probability of winning of Geeta is $0.27$.**

**Note:**

We can also face problems in place of “not E” $\left( {{\text{not E}}} \right)$ is given.

For instance, you have to find the probability of $P\left( {{\text{not E}}} \right)$so the manner of the calculating the probability of $P\left( {{\text{not E}}} \right)$ is the same as the probability of $P\left( {{\text{not E}}} \right)$directly write the following expression:$P\left( {{\text{not E}}} \right) = 1 - P(E)$

Memorizing this concept will save you a lot of time in solving questions in the competitive exam or in the test.

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