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**Hint:**The total class can be written as sum of number of boys and girls or it can be represented as,

\[\text{Number of boys }+\text{ Number of girls }=\text{ 48}\].

Now as we know the number of girls is \[\dfrac{3}{5}\] of the number of boys so substitute it and hence find the number of boys.

__Complete step-by-step answer__:In the question we are told that in a class of 48 students the number of girls is three-fifth then the number of boys. So, we have to find a number of boys.

So, we can write according to the question,

\[\text{Number of girls}=\dfrac{3}{5}\times \text{ number of boys}\text{.}\]

As we know that total strength of class which is 48. So we can also tell that the number of boys + number of boys is equal to 48.

Now we know that the number of girls is equal to \[\left( \dfrac{3}{5} \right)\] times the number of boys. So we can use it as,

Number of boy’s \[+\dfrac{3}{5}\] number of boys

\[\Rightarrow \text{number of boys}\left\{ 1+\dfrac{3}{5} \right\}\]

\[\Rightarrow \text{number of boys}\times \dfrac{8}{5}\]

Now we can say that the number of boys \[\times \dfrac{8}{5}\] can be written as 48.

So,

\[\dfrac{8}{5}\times number\text{ of boys=48}\]

we can also write,

\[Number\text{ of boys=48}\times \dfrac{8}{5}\]

Now on simplification we can say that the number of boys is 30.

**Hence, the correct option is 'B'.**

**Note**: We can take the number of boys as x. So, the number of girls will be \[\dfrac{3x}{5}\] hence, we can write \[x+\dfrac{3x}{5}=48\] and then solve for x to get the answer.

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