
If two constraints do not intersect in the positive quadrant of the graph, then
A. The problem is infeasible
B. The solution is unbounded
C. One of the constraints is redundant
D. None of the above
Answer
504.9k+ views
Hint: Hint: Here, we will determine the answer of the given condition by the help of the assumptions (properties) taken of the linear programming.
Complete step by step answer:
We are given the condition that if two constraints do not intersect in the positive quadrant of the graph, then we need to determine the nature of the solution obtained.
For this, we will recall the properties of linear programming.
The number of constraints should be expressed in the quantitative terms and it must be non – negative.
The relationship between the constraints and the objective functions should be linear.
The linear (objective) function is to be optimized (reformed to a certain extent).
Now we have the condition i. e., the constraints must be non – negative. This non – negativity condition is applied because a variable can not take negative value because it is impossible to get negative capital values for anything like land, labour, etc.
Therefore, due to condition I, the feasible region can only exist in Quadrant I.
Hence, we can say that the problem is infeasible.
Option(A) is correct.
Note:: In mathematics, the method of reforming the algebraic operations provided with some constraints. The constraints can be equalities or inequalities. We use this method to either maximize or minimize the value of the given function. It is used in mathematics (majorly) as well as in other branches such as statistics and economics.
Complete step by step answer:
We are given the condition that if two constraints do not intersect in the positive quadrant of the graph, then we need to determine the nature of the solution obtained.
For this, we will recall the properties of linear programming.
The number of constraints should be expressed in the quantitative terms and it must be non – negative.
The relationship between the constraints and the objective functions should be linear.
The linear (objective) function is to be optimized (reformed to a certain extent).
Now we have the condition i. e., the constraints must be non – negative. This non – negativity condition is applied because a variable can not take negative value because it is impossible to get negative capital values for anything like land, labour, etc.
Therefore, due to condition I, the feasible region can only exist in Quadrant I.
Hence, we can say that the problem is infeasible.
Option(A) is correct.
Note:: In mathematics, the method of reforming the algebraic operations provided with some constraints. The constraints can be equalities or inequalities. We use this method to either maximize or minimize the value of the given function. It is used in mathematics (majorly) as well as in other branches such as statistics and economics.
Recently Updated Pages
Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Earth rotates from West to east ATrue BFalse class 6 social science CBSE

The easternmost longitude of India is A 97circ 25E class 6 social science CBSE

Write the given sentence in the passive voice Ann cant class 6 CBSE

Convert 1 foot into meters A030 meter B03048 meter-class-6-maths-CBSE

What is the LCM of 30 and 40 class 6 maths CBSE

Trending doubts
Which one is a true fish A Jellyfish B Starfish C Dogfish class 10 biology CBSE

Dr BR Ambedkars fathers name was Ramaji Sakpal and class 10 social science CBSE

Write examples of herbivores carnivores and omnivo class 10 biology CBSE

What is the next number in the sequence 77493618 class 10 maths CBSE

Which is the second highest peak in India A Kanchenjunga class 10 social science CBSE

How do you split the middle term in quadratic equa class 10 maths CBSE
