Question

# If the eight-digit number 2575d568 is divisible by 54 and 87 the value of digit d isa) 4b) 7c) 0d) 8

Hint: We need to find the value of digit d in the eight-digit number 2575d568. As we know that 2575d568 is divisible by 54 and 87. So, we can say that it is also divisible by the factors of 54 and 87. So, we need to find the factors of 54 and 87 first and then with the help of the divisibility rule for each factor, find the value of digit d.

By the prime-factorization method, we can find the factors of 54 and 87. So, we have:
Factors of 54 are: $54=2\times 3\times 3\times 3=2\times 27$
Factors of 87 are: $87=3\times 29$
So, the number 2575d568 to be divisible by 54 and 87, it should be divisible by 2, 27, and 29.
Since the unit’s digit of the number is an even number, therefore 2575d568 is always divisible by 2.
Since both 54 and 87 have 3 as their common factor. So, the eight-digit number 2575d568 must be at least divisible by 3.
To check whether a number is divisible by 3 we need to follow the divisibility rule by 3. It says that a number is divisible by 3 when the sum of digits is divisible by 3.
Example: $6561\Rightarrow 6+5+6+1=18$ is divisible by 3.
So, to find whether 2575d568 is divisible by 3 or not we need to check if the sum of digits of the number is divisible by 3 or not.
Therefore, we can write:
\begin{align} & \Rightarrow 2+5+7+5+d+5+6+8 \\ & \Rightarrow 38+d \\ \end{align}
So, we need to put a one-digit value of d that makes $38+d$ divisible by 3.
i.e. d = 1, 4 or 7
If we add d=1, 4 or 7 in $38+d$ we get 39, 42 or 45 which are divisible by 3.
So, for d=1, 4 or 7, the number 2575d568 is divisible by 3. Hence the number would be divisible by 27.

But we need to check if for d=1, 4 or 7 the number 2575d568 is divisible by 29.
Put d=1, 4 or 7 in 2575d568, and check whether the number is divisible by 29. We get to know that for d=7, the number 2575d568 is divisible by 29.
Hence for d=7, the number 2575d568 is divisible by 54 and 87 both.

So, the correct answer is “Option b”.

Note: While checking that if the number 2575d568 is divisible by 3, we get three values of d = 1, 4, and 7. Don’t assume that the number will be divisible by 54 and 87 deliberately. The first check for other factors, i.e. 27 and 29 then confirm if it is divisible or not.