Answer
Verified
426k+ views
Hint: Here to proceed the solution we need to know the multiples of 3 and 6. Make set A and set B as per given condition.
Here we are given with two sets where with the condition, Where
A = $\{ x \in {\rm N}:{\text{x is a multiple of }}3\} $
Here set A is a multiple of 3 which are natural numbers.
Then $A = \{ 3,6,9,12,15,18,.......\} $
$B = \{ x \in {\rm N}:{\text{x is a multiple of 6}}\} $
Here set B is a multiple of 6 which are natural numbers.
Then $B = \{ 6,12,18,24,.....\} $
Now we got both the values of set A and set B
Then
$
A - B = \{ 3,6,9,12,15,18,.....\} - \{ 6,12,18,24,30,....\} \\
A - B = \{ 3,9,12,15,21,.....\} \\
$
Here A-B means we have removed the element of set B from set A.
Option C is the correct answer.
NOTE: In these problems first we have to find the value of set A by given condition and in the same way we have to find the values of set B .Later we have to find A-B which means we have to subtract values of set B from set A. In this type of problem mainly we have to focus on the conditions given to the sets because different sets have different conditions.
Here we are given with two sets where with the condition, Where
A = $\{ x \in {\rm N}:{\text{x is a multiple of }}3\} $
Here set A is a multiple of 3 which are natural numbers.
Then $A = \{ 3,6,9,12,15,18,.......\} $
$B = \{ x \in {\rm N}:{\text{x is a multiple of 6}}\} $
Here set B is a multiple of 6 which are natural numbers.
Then $B = \{ 6,12,18,24,.....\} $
Now we got both the values of set A and set B
Then
$
A - B = \{ 3,6,9,12,15,18,.....\} - \{ 6,12,18,24,30,....\} \\
A - B = \{ 3,9,12,15,21,.....\} \\
$
Here A-B means we have removed the element of set B from set A.
Option C is the correct answer.
NOTE: In these problems first we have to find the value of set A by given condition and in the same way we have to find the values of set B .Later we have to find A-B which means we have to subtract values of set B from set A. In this type of problem mainly we have to focus on the conditions given to the sets because different sets have different conditions.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
The branch of science which deals with nature and natural class 10 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Define absolute refractive index of a medium
Find out what do the algal bloom and redtides sign class 10 biology CBSE
Prove that the function fleft x right xn is continuous class 12 maths CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Summary of the poem Where the Mind is Without Fear class 8 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Write an application to the principal requesting five class 10 english CBSE
What organs are located on the left side of your body class 11 biology CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE