If a gas has $'n'$ degrees of freedom, the ratio of the specific heats of the gas $\gamma $ is
$A)\text{ }\dfrac{1+n}{2}$
$B)\text{ 1+}\dfrac{n}{2}$
$C)\text{ 1+}\dfrac{1}{n}$
$D)\text{ 1+}\dfrac{2}{n}$
Answer
654.3k+ views
Hint: We can find the specific heats by finding the internal energy of one mole of gas and relating it to the specific heat capacity at constant volume. From this we can get the specific heat at constant pressure by relating it with the universal gas constant. Therefore, we get the two specific heats and can find their ratio.
Formula used:
$E=\dfrac{1}{2}nRT$
$\dfrac{dE}{dT}={{C}_{V}}$
${{C}_{P}}-{{C}_{V}}=R$
Complete step-by-step answer:
First, we will try to find the specific heat capacity at constant volume for the gas by finding the internal energy of one mole of the gas.
The internal energy of one mole of a gas with $n$ degrees of freedom is given by
$E=\dfrac{1}{2}nRT$ --(1)
Where $T$ is the temperature of the gas and $R=8.314J.mo{{l}^{-1}}{{K}^{-1}}$ is the universal gas constant.
Now, the specific heat at constant volume ${{C}_{V}}$ of a gas is related to its internal energy $E$ by
${{C}_{V}}=\dfrac{dE}{dT}$ --(2)
Putting (1) in (2), we get,
${{C}_{V}}=\dfrac{d\left( \dfrac{1}{2}nRT \right)}{dT}=\dfrac{1}{2}nR$ --(3)
Now, the specific heat at constant volume ${{C}_{V}}$ is related to the specific heat at constant pressure ${{C}_{P}}$ by
${{C}_{P}}={{C}_{V}}+R$
Using (3), we get,
${{C}_{P}}=\dfrac{1}{2}nR+R=R\left( \dfrac{1}{2}n+1 \right)$ --(4)
Now, ratio of the specific heats $\gamma $ of a gas is the ratio of the specific heat at constant pressure ${{C}_{P}}$ to the specific heat at constant volume ${{C}_{V}}$. Therefore,
$\gamma =\dfrac{{{C}_{P}}}{{{C}_{V}}}$
Using (3) and (4), we get,
$\gamma =\dfrac{R\left( \dfrac{1}{2}n+1 \right)}{\dfrac{1}{2}nR}=\dfrac{\dfrac{1}{2}nR\left( 1+\dfrac{1}{\dfrac{1}{2}n} \right)}{\dfrac{1}{2}nR}=\left( 1+\dfrac{1}{\dfrac{1}{2}n} \right)=1+\dfrac{2}{n}$
Hence, the required value of $\gamma $ is $1+\dfrac{2}{n}$.
Therefore, the correct option is $D)\text{ 1+}\dfrac{2}{n}$.
Note: Students get confused while writing the ratio of the specific heats and tend to write the ratio with the specific heat capacity at constant volume in the numerator. A good way to remember the ratio is to keep in mind that the ratio is always greater than one and the specific heat at constant pressure is always greater than the specific heat at constant volume and therefore, if the ratio has to be greater than tone, the specific heat at constant pressure should be in the numerator.
Formula used:
$E=\dfrac{1}{2}nRT$
$\dfrac{dE}{dT}={{C}_{V}}$
${{C}_{P}}-{{C}_{V}}=R$
Complete step-by-step answer:
First, we will try to find the specific heat capacity at constant volume for the gas by finding the internal energy of one mole of the gas.
The internal energy of one mole of a gas with $n$ degrees of freedom is given by
$E=\dfrac{1}{2}nRT$ --(1)
Where $T$ is the temperature of the gas and $R=8.314J.mo{{l}^{-1}}{{K}^{-1}}$ is the universal gas constant.
Now, the specific heat at constant volume ${{C}_{V}}$ of a gas is related to its internal energy $E$ by
${{C}_{V}}=\dfrac{dE}{dT}$ --(2)
Putting (1) in (2), we get,
${{C}_{V}}=\dfrac{d\left( \dfrac{1}{2}nRT \right)}{dT}=\dfrac{1}{2}nR$ --(3)
Now, the specific heat at constant volume ${{C}_{V}}$ is related to the specific heat at constant pressure ${{C}_{P}}$ by
${{C}_{P}}={{C}_{V}}+R$
Using (3), we get,
${{C}_{P}}=\dfrac{1}{2}nR+R=R\left( \dfrac{1}{2}n+1 \right)$ --(4)
Now, ratio of the specific heats $\gamma $ of a gas is the ratio of the specific heat at constant pressure ${{C}_{P}}$ to the specific heat at constant volume ${{C}_{V}}$. Therefore,
$\gamma =\dfrac{{{C}_{P}}}{{{C}_{V}}}$
Using (3) and (4), we get,
$\gamma =\dfrac{R\left( \dfrac{1}{2}n+1 \right)}{\dfrac{1}{2}nR}=\dfrac{\dfrac{1}{2}nR\left( 1+\dfrac{1}{\dfrac{1}{2}n} \right)}{\dfrac{1}{2}nR}=\left( 1+\dfrac{1}{\dfrac{1}{2}n} \right)=1+\dfrac{2}{n}$
Hence, the required value of $\gamma $ is $1+\dfrac{2}{n}$.
Therefore, the correct option is $D)\text{ 1+}\dfrac{2}{n}$.
Note: Students get confused while writing the ratio of the specific heats and tend to write the ratio with the specific heat capacity at constant volume in the numerator. A good way to remember the ratio is to keep in mind that the ratio is always greater than one and the specific heat at constant pressure is always greater than the specific heat at constant volume and therefore, if the ratio has to be greater than tone, the specific heat at constant pressure should be in the numerator.
Recently Updated Pages
Lysosomes are known as suicidal bags of cell why class 11 biology CBSE

Father s age is three times the sum of the ages of-class-11-maths-CBSE

Give a comparative account of the classes of kingdom class 11 biology CBSE

The ceiling of a long hall is 25m high What is the class 11 physics CBSE

Name the Largest and the Smallest Cell in the Human Body ?

Draw a welllabelled diagram of a plant cell class 11 biology CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

10 examples of diffusion in everyday life

