
How do you solve for r in \[s = 2\pi rh\] ?
Answer
552.3k+ views
Hint:To find the value of r, just isolate the terms with respect to the variable asked i.e., here in this question we need to divide both sides of the expression by \[2\pi h\], hence by solving this we can get the expression of r.
Complete step by step answer:
The given expression is
\[s = 2\pi rh\]
As we need to solve for r, hence rewriting the given expression as
\[2\pi rh = s\]
Now divide both sides of the expression by \[2\pi h\]as
\[\dfrac{{2\pi rh}}{{2\pi h}} = \dfrac{s}{{2\pi h}}\]
The obtained expression consists of common terms i.e., 2 is common, hence by simplifying the terms we get
\[\dfrac{{\pi rh}}{{\pi h}} = \dfrac{s}{{2\pi h}}\]
The obtained expression consists of common terms i.e., \[\pi \] is common, hence by simplifying the terms we get
\[\dfrac{{rh}}{h} = \dfrac{s}{{2\pi h}}\]
The obtained expression consists of common terms i.e., h is common, hence by simplifying the terms we get
\[r = \dfrac{s}{{2\pi h}}\]
Therefore, the expression of r is \[r = \dfrac{s}{{2\pi h}}\]
Additional information: We have 4 ways of solving one-step equations: Adding, Subtracting, multiplication and division. If we add the same number to both sides of an equation, both sides will remain equal.
Note: The key point to find the value of variable asked is Isolate r on one side of the algebraic equation by subtracting the sum that appears on the same side of the equation as the r and that equals sign verifies the condition that the inherent value on the left is the same as the inherent value on the right. So, what you do to one side you also have to do to the right. Otherwise, one side is not the same value as the other.
Complete step by step answer:
The given expression is
\[s = 2\pi rh\]
As we need to solve for r, hence rewriting the given expression as
\[2\pi rh = s\]
Now divide both sides of the expression by \[2\pi h\]as
\[\dfrac{{2\pi rh}}{{2\pi h}} = \dfrac{s}{{2\pi h}}\]
The obtained expression consists of common terms i.e., 2 is common, hence by simplifying the terms we get
\[\dfrac{{\pi rh}}{{\pi h}} = \dfrac{s}{{2\pi h}}\]
The obtained expression consists of common terms i.e., \[\pi \] is common, hence by simplifying the terms we get
\[\dfrac{{rh}}{h} = \dfrac{s}{{2\pi h}}\]
The obtained expression consists of common terms i.e., h is common, hence by simplifying the terms we get
\[r = \dfrac{s}{{2\pi h}}\]
Therefore, the expression of r is \[r = \dfrac{s}{{2\pi h}}\]
Additional information: We have 4 ways of solving one-step equations: Adding, Subtracting, multiplication and division. If we add the same number to both sides of an equation, both sides will remain equal.
Note: The key point to find the value of variable asked is Isolate r on one side of the algebraic equation by subtracting the sum that appears on the same side of the equation as the r and that equals sign verifies the condition that the inherent value on the left is the same as the inherent value on the right. So, what you do to one side you also have to do to the right. Otherwise, one side is not the same value as the other.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

