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# How do you solve $c+(4-3c)-2=0$?

Last updated date: 13th Jun 2024
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The given equation says that $c+(4-3c)-2=0$ …. (i)
To find the value of c that satisfies the above given equation we shall analyse the given equation and then figure out to find the required value of c. In equation (i), we can use a bracket with some inside it, on the left hand side of the equation. Let the first open up that bracket. When we open up that bracket the equation will change to $c+4-3c-2=0$.
The thing that we can next do is that we can club the terms that are multiples of c on one side of the equation (let us say left hand side) and we can club the constant terms on the other side of the equation (i.e. right hand side).When we do this the equation changes to $c-3c=2-4$Then, the further calculation gives us that $-2c=-2$. Then this means that $c=1$.
Therefore, $c=1$ is the value of c that satisfies the given equation.