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**Hint:**Here we will factorize the given polynomial by using the factor theorem. First, we will find a value of \[x\] which satisfies the polynomial by hit and trial method. Then we will take that factor and divide the polynomial by it, to find the next set of factors.

**Complete step-by-step answer:**

We have to factorize polynomials \[{x^2} - 3x\].

First, we need to know at least one zero of the polynomial, so we will use the hit and trial method.

Let us check whether \[x = 0\] satisfies the polynomial or not.

Putting \[x = 0\] in \[{x^2} - 3x\], we get,

\[{0^2} - 3 \times 0 = 0\]

So \[x = 0\] is a factor as it satisfies the polynomial.

So, one factor is \[\left( {x - 0} \right)\] or we can say \[x\] is the factor of the given polynomial.

Now we will divide the polynomial \[{x^2} - 3x\] by \[x\] and take out the common term from both the terms of the polynomial. Therefore, we get

\[\dfrac{{{x^2} - 3x}}{x} = \dfrac{{x\left( {x - 3} \right)}}{x}\]

Cancelling out the common terms, we get

\[ \Rightarrow \dfrac{{{x^2} - 3x}}{x} = \left( {x - 3} \right)\]

So, we get the quotient as \[\left( {x - 3} \right)\].

So, we get the zeroes of the given polynomial as \[x = 3\].

**Hence, the factors of the polynomial are \[\left( x \right)\left( {x - 3} \right)\]**

**Note:**

Factor theorem states that if a polynomial \[f\left( x \right)\] of degree \[n \ge 1\] and ‘\[a\]’ is any real number then, if \[f\left( a \right) = 0\] then only \[\left( {x - a} \right)\] is a factor of the polynomial. The two problems where Factor Theorem is usually applied are when we have to factorize a polynomial and also when we have to find the roots of the polynomial. It is also used to remove known zeros from a polynomial while leaving all unknown zeros intact. It is a special case of a polynomial remainder theorem.

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