Answer
385.5k+ views
Hint: In the question we need to factorise the given equation. We can observe that the given equation is a quadratic equation. Generally, we will follow different methods for different types of equations. For the quadratic equation which is in the form of $a{{x}^{2}}+bx+c$, we will break the middle term into two parts like $b={{x}_{1}}+{{x}_{2}}$ such that ${{x}_{1}}.{{x}_{2}}=ac$. So, we will first calculate the value of $ac$ and we will write the factors of the calculated $ac$ and choose two factors such that they satisfy the above-mentioned conditions. After getting the values of ${{x}_{1}}$, ${{x}_{2}}$ we will break the middle term and simplify the equation by taking appropriate terms as common. After taking the terms as common we will get our required result.
Given that, ${{x}^{2}}-8x+16$.
Comparing the above equation with $a{{x}^{2}}+bx+c$, then we can write
Coefficient of ${{x}^{2}}$ is $a=1$.
Coefficient of $x$ is $b=-8$.
Constant is $c=16$.
Now the value of $ac$ is given by
$\begin{align}
& ac=1\left( 16 \right) \\
& \Rightarrow ac=16 \\
\end{align}$
Here we have the value of $ac$ as $16$. We know that the factors for $16$ are $1$, $2$, $4$, $8$, $16$, $45$.
From the above factors we can observe that
$\begin{align}
& -4-4=8 \\
& -4\times -4=16 \\
\end{align}$
So, we can break the middle term $-8x$ as $-8x=-4x-4x$. From this value, we are going to write the given equation as
$\Rightarrow {{x}^{2}}-8x+16={{x}^{2}}-4x-4x+16$
Taking $x$ as common from ${{x}^{2}}-4x$ and $-4$ as common from $-4x+16$, then the above equation is modified as
$\Rightarrow {{x}^{2}}-8x+16=x\left( x-4 \right)-4\left( x-4 \right)$
Again, taking $x-4$ as common on RHS of the above equation, then we will get
$\Rightarrow {{x}^{2}}-8x+16=\left( x-4 \right)\left( x-4 \right)$
Hence the factors of the given equation are $x-4$ and $x-4$.
We can also write the above equation as
$\Rightarrow {{x}^{2}}-8x+16={{\left( x-4 \right)}^{2}}$
Note:
In this problem, they have only asked to factorize the given equation, so we have ended our procedure after calculating the factors. If they have asked to solve the equation or asked to find the roots, then we need to equate the given equation to zero and we will find the values of $x$.
Given that, ${{x}^{2}}-8x+16$.
Comparing the above equation with $a{{x}^{2}}+bx+c$, then we can write
Coefficient of ${{x}^{2}}$ is $a=1$.
Coefficient of $x$ is $b=-8$.
Constant is $c=16$.
Now the value of $ac$ is given by
$\begin{align}
& ac=1\left( 16 \right) \\
& \Rightarrow ac=16 \\
\end{align}$
Here we have the value of $ac$ as $16$. We know that the factors for $16$ are $1$, $2$, $4$, $8$, $16$, $45$.
From the above factors we can observe that
$\begin{align}
& -4-4=8 \\
& -4\times -4=16 \\
\end{align}$
So, we can break the middle term $-8x$ as $-8x=-4x-4x$. From this value, we are going to write the given equation as
$\Rightarrow {{x}^{2}}-8x+16={{x}^{2}}-4x-4x+16$
Taking $x$ as common from ${{x}^{2}}-4x$ and $-4$ as common from $-4x+16$, then the above equation is modified as
$\Rightarrow {{x}^{2}}-8x+16=x\left( x-4 \right)-4\left( x-4 \right)$
Again, taking $x-4$ as common on RHS of the above equation, then we will get
$\Rightarrow {{x}^{2}}-8x+16=\left( x-4 \right)\left( x-4 \right)$
Hence the factors of the given equation are $x-4$ and $x-4$.
We can also write the above equation as
$\Rightarrow {{x}^{2}}-8x+16={{\left( x-4 \right)}^{2}}$
Note:
In this problem, they have only asked to factorize the given equation, so we have ended our procedure after calculating the factors. If they have asked to solve the equation or asked to find the roots, then we need to equate the given equation to zero and we will find the values of $x$.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)