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# How do you evaluate ${{\log }_{2}}16$?

Last updated date: 13th Jun 2024
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Hint: Convert the argument of the given logarithmic expression, i.e., 16 into the exponential form having base 2. Now, apply the logarithmic formula given as: - $\log {{a}^{m}}=m\log a$ to simplify the expression. Now, use the identity: - ${{\log }_{n}}n=1$ to get the answer. Here, ‘n’ denotes the same argument and base of the logarithmic function and n > 0, $n\ne 1$.

Here, we have been provided with the logarithmic expression ${{\log }_{2}}16$ and we are asked to find its exact value.
$\Rightarrow E={{\log }_{2}}16$
$\Rightarrow E={{\log }_{2}}\left( {{2}^{4}} \right)$
Using the logarithmic identity: - $\log {{a}^{m}}=m\log a$, we get,
$\Rightarrow E=4{{\log }_{2}}2$
Now, since the base and argument of the logarithmic expression is same in the above obtained expression, so applying the formula ${{\log }_{n}}n=1$, where n > 0 and $n\ne 1$, we get,
\begin{align} & \Rightarrow E=4\times 1 \\ & \Rightarrow E=4 \\ \end{align}
Hence, the value of the given logarithmic expression ${{\log }_{2}}16$ is 4.
Note: One may note that common log has base 10 and natural log has base e, where $e\simeq 2.71$. Natural log is denoted by ln. Here, in the above question the base of the log is 2 so it is neither a common log nor a natural log. Note that logarithm is the inverse process of exponentiation so we can also solve the above question by converting the given logarithmic form of the expression into its exponential form. What we can do is we will use the basic definition of logarithmic to write: - if ${{\log }_{2}}16=x$ then ${{2}^{x}}=16$. In the next step write $16={{2}^{4}}\Rightarrow {{2}^{x}}={{2}^{4}}$ and then remove the base 2 from both the sides and equate the exponents. We will solve for the value of x to get the answer.