Courses for Kids
Free study material
Offline Centres

How many grams are in a mole of hydrogen chloride?

Last updated date: 03rd Mar 2024
Total views: 340.5k
Views today: 6.40k
IVSAT 2024
340.5k+ views
Hint: The molar mass of a compound is specified by the sum of the usual atomic weight (namely, the ordinary relative atomic mass) of the atoms which method the compound multiplied by the molar mass constant. Multiplying by the molar mass constant type assures that the scheming is dimensionally accurate: standard relative atomic masses are dimensionless amounts (i.e., pure numbers) while molar masses have units (in this case, grams/mole).

Complete step by step answer:
The sum of the atomic mass of hydrogen and chlorine: \[\left( {1.00794 + 35.45} \right) \cdot g \cdot mo{l^{ - 1}} = {\text{ }}36.46 \cdot g \cdot mo{l^{ - 1}}\] .
Avogadro's number \[ = \;6.022 \times {10^{23}} \cdot mo{l^{ - 1}}\] . The specific \[HCl\] molecules are in a mass of \[36.46 \cdot g\;\] of the gas.
The molar mass of \[HCl\] is \[36.46 \cdot g \cdot mo{l^{ - 1}}\] .

Additional information:
The compound Hydrogen Chloride has the chemical formula \[HCl\] .Hydrogen chloride \[\left( {{{HCl}}} \right),\] a compound of the elements hydrogen and chlorine, a gas at room temperature and pressure. A resolution of the gas in water is called Hydrochloric Acid.

Note: we at present have the Molar mass of the substance calculator, which calculates molar mass for assumed substance with Periodic table handbook. It is recycled in the calculator inferior to to parse chemical compound formulas and get molar mass.
The adder below analyzes mass of the substance in grams or mass of the substance in moles dependent on the user's input. It also shows molar mass of the chemical compound and details of its calculation just for orientation.
At all times use the upper case for the first character in the element name and the inferior case for the second character as in the periodic table. Equate: \[{{Co}}\] - cobalt and \[{{CO}}\] - carbon monoxide. Therefore, \[{{N}}{{{a}}_{{3}}}{{P}}{{{O}}_{{4}}}\] — correct notation, \[{{na3po4}}/{{NA3PO4}}\] — incorrect notation.

Recently Updated Pages
Trending doubts