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# For the following system of equations determine the value of k for which the given system of equations has infinitely many solutions.$\left( {{\text{k - 3}}} \right){\text{x + 3y = k}} \\ {\text{kx + ky = 12}} \\$  Hint:- For the system of equations to have infinitely many solutions the ratios of coefficients of x ,y and constant term should be equal.

Given,
$\left( {{\text{k - 3}}} \right){\text{x + 3y = k and kx + ky = 12}}$ .
Let
$\left( {{\text{k - 3}}} \right){\text{x + 3y = k }} \cdots \left( 1 \right) \\ {\text{kx + ky = 12 }} \cdots \left( 2 \right) \\$
For a general system of equations of two variables, let the equations be
${{\text{a}}_1}{\text{x + }}{{\text{b}}_1}{\text{y = }}{{\text{c}}_1}{\text{ }} \cdots \left( 3 \right) \\ {{\text{a}}_2}{\text{x + }}{{\text{b}}_2}{\text{y = }}{{\text{c}}_2}{\text{ }} \cdots \left( 4 \right) \\$
The equations will have infinite solution if and only if,
$\dfrac{{{{\text{a}}_1}}}{{{{\text{a}}_2}}} = \dfrac{{{{\text{b}}_1}}}{{{{\text{b}}_2}}} = \dfrac{{{{\text{c}}_1}}}{{{{\text{c}}_2}}}$

On comparing the coefficients of equation (1) and (3) we get,
${{\text{a}}_1}{\text{ = k - 3, }}{{\text{b}}_1}{\text{ = 3 and }}{{\text{c}}_1}{\text{ = k }} \cdots \left( 5 \right)$

On comparing the coefficients of equation (2) and (4) we get,
${{\text{a}}_2}{\text{ = k, }}{{\text{b}}_2}{\text{ = k and }}{{\text{c}}_2}{\text{ = 12 }} \cdots \left( 6 \right)$

Now, dividing the equation (5) and (6), we get
$\dfrac{{{\text{k - 3}}}}{{\text{k}}} = \dfrac{3}{{\text{k}}}{\text{ and }}\dfrac{3}{{\text{k}}} = \dfrac{{\text{k}}}{{12}}$

Solving above equations, we get
$\left( {{\text{k - 3}}} \right){\text{k = 3k and }}{{\text{k}}^2}{\text{ = 36}} \\ {\text{k - 3 = 3 and k = }}\sqrt {36} \\ {\text{k = 6 }} \\$
Both the equations will satisfy for k =6. Hence , the required answer is 6.
The equations will be 3x + 3y=6 and 6x + 6y =12.

Note:- The system of equations having infinite solutions is consistent and dependent. Equations of two variables must have the same slope and same y-intercept for having infinite solutions.

View Notes
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