Answer
Verified
332.6k+ views
Hint: To find the answer you have to use the Arrhenius equation and from there you can easily calculate the value of the rate constant at 300 K as you already have the value at 280 K.
Complete step by step answer:
We know that the Arrhenius equation is represented as,
$k\quad =\quad Ae^{ -Ea/RT }$
When we have two rate constants at two different temperatures. We can also write this as,
$log\dfrac { { k }_{ 2 } }{ { k }_{ 1 } } \quad =\quad \dfrac { { E }_{ a } }{ 2.303 } \left( \dfrac { { T }_{ 2 }-{ T }_{ 1 } }{ { T }_{ 1 }{ T }_{ 2 } } \right)$
Here,
${ k }_{ 2 }$ = we have to calculate
${ k }_{ 1 }$ = 1.6 x $10^{ 6 }s^{ -1 }$
${ T }_{ 2 }$ = 300 K
${ T }_{ 1 }$ = 280 K
${ E }_{ a }$ = 0
Now, just insert the values in the above equation -
$\Rightarrow log\dfrac { { k }_{ 2 } }{ { k }_{ 1 } } \quad =\quad \dfrac { 0 }{ 2.303 } \left( \dfrac { 300-280 }{ 280\quad \times \quad 300 } \right) $
$\Rightarrow log\dfrac { { k }_{ 2 } }{ 1.6\quad \times \quad 10^{ 6 } } \quad =\quad 0$
$\Rightarrow \dfrac { { k }_{ 2 } }{ 1.6\quad \times \quad 10^{ 6 } } \quad =\quad antilog(0)$
$\Rightarrow \dfrac { { k }_{ 2 } }{ 1.6\quad \times \quad 10^{ 6 } } \quad =\quad 1$
$\Rightarrow { k }_{ 2 }$ = 1.6 x $10^{ 6 }s^{ -1 }$ = ${ k }_{ 1 }$
Here we can see that this value of the rate constant at 280 K is exactly the same as the value of the rate constant at 300 K. So, we can say that there is no effect.
Therefore, we can conclude that the correct answer to this question is option A.
Note: We should know the relation of activation energy with temperature - As temperature increases, molecules gain energy and move faster and faster. Therefore, the greater the temperature, the higher the probability that molecules will be moving with the necessary activation energy for a reaction to occur upon collision.
Complete step by step answer:
We know that the Arrhenius equation is represented as,
$k\quad =\quad Ae^{ -Ea/RT }$
When we have two rate constants at two different temperatures. We can also write this as,
$log\dfrac { { k }_{ 2 } }{ { k }_{ 1 } } \quad =\quad \dfrac { { E }_{ a } }{ 2.303 } \left( \dfrac { { T }_{ 2 }-{ T }_{ 1 } }{ { T }_{ 1 }{ T }_{ 2 } } \right)$
Here,
${ k }_{ 2 }$ = we have to calculate
${ k }_{ 1 }$ = 1.6 x $10^{ 6 }s^{ -1 }$
${ T }_{ 2 }$ = 300 K
${ T }_{ 1 }$ = 280 K
${ E }_{ a }$ = 0
Now, just insert the values in the above equation -
$\Rightarrow log\dfrac { { k }_{ 2 } }{ { k }_{ 1 } } \quad =\quad \dfrac { 0 }{ 2.303 } \left( \dfrac { 300-280 }{ 280\quad \times \quad 300 } \right) $
$\Rightarrow log\dfrac { { k }_{ 2 } }{ 1.6\quad \times \quad 10^{ 6 } } \quad =\quad 0$
$\Rightarrow \dfrac { { k }_{ 2 } }{ 1.6\quad \times \quad 10^{ 6 } } \quad =\quad antilog(0)$
$\Rightarrow \dfrac { { k }_{ 2 } }{ 1.6\quad \times \quad 10^{ 6 } } \quad =\quad 1$
$\Rightarrow { k }_{ 2 }$ = 1.6 x $10^{ 6 }s^{ -1 }$ = ${ k }_{ 1 }$
Here we can see that this value of the rate constant at 280 K is exactly the same as the value of the rate constant at 300 K. So, we can say that there is no effect.
Therefore, we can conclude that the correct answer to this question is option A.
Note: We should know the relation of activation energy with temperature - As temperature increases, molecules gain energy and move faster and faster. Therefore, the greater the temperature, the higher the probability that molecules will be moving with the necessary activation energy for a reaction to occur upon collision.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
What is BLO What is the full form of BLO class 8 social science CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Fill the blanks with proper collective nouns 1 A of class 10 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
What organs are located on the left side of your body class 11 biology CBSE
Name 10 Living and Non living things class 9 biology CBSE