Question

# Find the value of k for which the quadratic equation $2{x^2} + kx + 3 = 0$ has two real equal roots.

A quadratic equation $a{x^2} + bx + c = 0$ has two real equal roots when ${b^2} - 4ac = 0$ ( discriminant = 0 )
${k^2} - 4 \times 2 \times 3 = 0$
${k^2} = 24$
$k = \pm 2\sqrt 6$
Therefore the equation has two real equal roots for k =$\pm 2\sqrt 6$.