find the sum of interior angles of a polygon with sides.
Last updated date: 20th Mar 2023
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Answer
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Hint: Start by applying the formula to find the sum of interior angle which is $\left( {2n - 4} \right)90$
Sides= $8$
Sum of interior angles of polygon $ = \left( {2n - 4} \right)90$
Here, the value of $n$is $8$, therefore,
$ = \left( {16 - 4} \right)90$
$ = \left( {12} \right)90$
$ = 1080$
Hence, the answer is $1080$.
Note: We have used the formula of finding the sum of interior angles of a polygon.so that sum of interior angles can be found
Sides= $8$
Sum of interior angles of polygon $ = \left( {2n - 4} \right)90$
Here, the value of $n$is $8$, therefore,
$ = \left( {16 - 4} \right)90$
$ = \left( {12} \right)90$
$ = 1080$
Hence, the answer is $1080$.
Note: We have used the formula of finding the sum of interior angles of a polygon.so that sum of interior angles can be found
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