Answer
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Hint: In order to solve this problem we need to factorize 49 then we have to take the square root of it. Doing this will solve the problems.
Complete step-by-step answer:
We have to find the square root of 49.
We know 49 can be written as 49 = 7x7=${7^2}$
So, after taking square root of it we get$\sqrt {49} = \sqrt {{7^2}} $
Square root means nothing but the number raised to the power $\dfrac{1}{2}$ (Example $\sqrt a = {a^{\dfrac{1}{2}}}$)
So, $\sqrt {49} = $$\sqrt {{7^2}} = {7^{2{\text{x}}\dfrac{1}{2}}} = {7^1} = 7$
Therefore the square root of 49 is 7.
So, the correct option is B.
Note: Whenever you face such types of problems of finding the square root of a number. Then try to factorize that number such that numbers are in pairs of two, those numbers will be written outside the square root and the numbers which are not is pair of two those numbers will be written inside the root as square root of a number is nothing but a number raised to the power $\dfrac{1}{2}$. Proceeding like this will give you the right solution.
Complete step-by-step answer:
We have to find the square root of 49.
We know 49 can be written as 49 = 7x7=${7^2}$
So, after taking square root of it we get$\sqrt {49} = \sqrt {{7^2}} $
Square root means nothing but the number raised to the power $\dfrac{1}{2}$ (Example $\sqrt a = {a^{\dfrac{1}{2}}}$)
So, $\sqrt {49} = $$\sqrt {{7^2}} = {7^{2{\text{x}}\dfrac{1}{2}}} = {7^1} = 7$
Therefore the square root of 49 is 7.
So, the correct option is B.
Note: Whenever you face such types of problems of finding the square root of a number. Then try to factorize that number such that numbers are in pairs of two, those numbers will be written outside the square root and the numbers which are not is pair of two those numbers will be written inside the root as square root of a number is nothing but a number raised to the power $\dfrac{1}{2}$. Proceeding like this will give you the right solution.
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