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Hint: Here to get the ratio of total surface area and lateral surface area of the cube let us divide their values from where we can get their ratio value.
Here we have to find the ratio of the total surface area and lateral surface area of the cube.
We know that
Total surface area of cube (TSA) = $6{a^2}$
Lateral surface area of cube (LSA) =$4{a^2}$
Therefore
TSA: LSA =$6{a^2}$: $4{a^2}$=3:2 (Where${a^2}$ get cancels)
Hence the ratio of the total surface area and lateral surface area of cube is 3:2
Note: Here we got the formulas of total surface area of the cube and lateral surface area of the cube and simplified the values to get the ratio of the two values. To get the ratio values we can also divide them.
Here we have to find the ratio of the total surface area and lateral surface area of the cube.
We know that
Total surface area of cube (TSA) = $6{a^2}$
Lateral surface area of cube (LSA) =$4{a^2}$
Therefore
TSA: LSA =$6{a^2}$: $4{a^2}$=3:2 (Where${a^2}$ get cancels)
Hence the ratio of the total surface area and lateral surface area of cube is 3:2
Note: Here we got the formulas of total surface area of the cube and lateral surface area of the cube and simplified the values to get the ratio of the two values. To get the ratio values we can also divide them.
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