Answer
Verified
479.7k+ views
Hint: Here we proceed the solution by considering all possible outcomes of three coins when they are tossed. So here we have to find the probability of at most two tails or at least two heads where at most indicates two or less than two.
Complete step-by-step answer:
Let set S be the sample space of all three possible outcomes of three coins tossed.
S= {HHH, HTH, THH, HHT, TTH, HTT, THT, TTT}
Here H denotes Heads and T denotes Tail
Now from the set S
The total number of outcomes = 8
Here we have to find probability of at most two tails or at least two heads
As we know that at most 2 means two or less than two. So now by using the at most condition, we can say
Number of outcomes with at-most two tails or at least two heads = 7
Now by using the total number of outcomes and number of outcomes with at-most two tails or at-least two heads we can find the required probability.
Therefore probability of at-most two tails and at least two in a toss of three coins =
$
= \dfrac{{{\text{Number of outcomes with at most 2tails or at least 2heads}}}}{{{\text{total number of outcomes}}}} \\
= \dfrac{7}{8} \\
$
Note: In this problem we have to focus on two words they are at-most and at-least these are the two key words the whole problem depends on these are conditions these are conditions given to solve the problem. Generally everyone will ignore these words which will affect the answer.
Complete step-by-step answer:
Let set S be the sample space of all three possible outcomes of three coins tossed.
S= {HHH, HTH, THH, HHT, TTH, HTT, THT, TTT}
Here H denotes Heads and T denotes Tail
Now from the set S
The total number of outcomes = 8
Here we have to find probability of at most two tails or at least two heads
As we know that at most 2 means two or less than two. So now by using the at most condition, we can say
Number of outcomes with at-most two tails or at least two heads = 7
Now by using the total number of outcomes and number of outcomes with at-most two tails or at-least two heads we can find the required probability.
Therefore probability of at-most two tails and at least two in a toss of three coins =
$
= \dfrac{{{\text{Number of outcomes with at most 2tails or at least 2heads}}}}{{{\text{total number of outcomes}}}} \\
= \dfrac{7}{8} \\
$
Note: In this problem we have to focus on two words they are at-most and at-least these are the two key words the whole problem depends on these are conditions these are conditions given to solve the problem. Generally everyone will ignore these words which will affect the answer.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE