Answer

Verified

383.4k+ views

**Hint:**To get the percentage of the given quantity in the form of $a\%$ of $b$, we will use the formula $\dfrac{a}{100}\times b$. Then, we will simplify it in the simplest form with the help of proper mathematical operations to get the required answer.

**Complete step by step answer:**

a. $25\%$ of $500$

Since, the formula for getting the percentage of the above given quantity is:

$\Rightarrow \dfrac{a}{100}\times b$

Where, $a=25$ and $b=500$.

Now, we will substitute the respective values of $a$ and $b$in the formula as:

$\Rightarrow \dfrac{25}{100}\times 500$

Here, we will get $12500$ after multiplying $25$ and $500$ from the above step as:

$\Rightarrow \dfrac{12500}{100}$

Using division, we will have:

$\Rightarrow 125$

Hence, the percentage of $25\%$ of $500$ is $125$.

b. $30\%$ of ₹$1200$

We will use the formula for getting the percentage of the above given quantity.

$\Rightarrow \dfrac{a}{100}\times b$

Where, $a=30$ and $b=1200$.

Substitute $30$ for $a$ and $1200$ for $b$in the formula as:

$\Rightarrow \dfrac{30}{100}\times 1200$

After multiplying $30$ and $1200$, we will get $36000$ from the above step as:

$\Rightarrow \dfrac{36000}{100}$

We will have $360$by division from the above step as:

$\Rightarrow 360$

Hence, the required answer is $360$.

c. $45\%$ of $500$ KM

For getting the percentage of the above given quantity, we can use the formula mentioned below:

$\Rightarrow \dfrac{a}{100}\times b$

Where, $a=45$ and $b=500$.

Substituting $30$ for $a$ and $1200$ for $b$ in the above formula as:

$\Rightarrow \dfrac{45}{100}\times 500$

Now, we will multiply $45$ with $500$ and will get $22500$ from the above step as:

$\Rightarrow \dfrac{22500}{100}$

By division, we will have $225$from the above step as:

$\Rightarrow 225$

Hence, the required value of the given quantity is $225$.

**Note:**We can check whether the procedure for obtaining the required value is correct or incorrect in the by using the following formula of getting percent of obtained value.

$=\dfrac{\text{Obtained value}}{\text{Total}}\times 100$

Check for $25\%$ of $500$ -

Since, the obtained value is $125$ and total is $500$. So, from the formula-

$=\dfrac{125}{500}\times 100$

Now, we will do the necessary mathematical calculation:

$\begin{align}

& =\dfrac{125}{5} \\

& =25\% \\

\end{align}$

Hence, the solution is correct.

For $30\%$ of ₹$1200$-

Since, the obtained value is $360$ and the total is $1200$. So, from the formula-

$=\dfrac{360}{1200}\times 100$

Now, we will do the necessary mathematical calculation:

$\begin{align}

& =\dfrac{360}{12} \\

& =30\% \\

\end{align}$

Hence, the solution is correct.

For $45\%$ of $500$ KM

Since, the obtained value is $225$ and the total is $500$. So, from the formula-

$=\dfrac{225}{500}\times 100$

Now, we will do the necessary mathematical calculation:

$\begin{align}

& =\dfrac{225}{5} \\

& =45\% \\

\end{align}$

Hence, the solution is correct.

Recently Updated Pages

Who among the following was the religious guru of class 7 social science CBSE

what is the correct chronological order of the following class 10 social science CBSE

Which of the following was not the actual cause for class 10 social science CBSE

Which of the following statements is not correct A class 10 social science CBSE

Which of the following leaders was not present in the class 10 social science CBSE

Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE

Trending doubts

Derive an expression for drift velocity of free electrons class 12 physics CBSE

Which are the Top 10 Largest Countries of the World?

Write down 5 differences between Ntype and Ptype s class 11 physics CBSE

The energy of a charged conductor is given by the expression class 12 physics CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Derive an expression for electric field intensity due class 12 physics CBSE

How do you graph the function fx 4x class 9 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Derive an expression for electric potential at point class 12 physics CBSE