Questions & Answers

Question

Answers

a. \[( - 8a + 11b - 4c - 9bc)\]

b. \[(8a + 11b - 4c - 9bc)\]

c. \[( - 8a - 11b - 4c - 9bc)\]

d. \[( - 8a - 11b + 4c - 9bc)\]

Answer
Verified

Initially we are given the task to find the excess of \[4(a - b - c)\] over \[3(a + b)\]. So, for that we will have to subtract \[3(a + b)\] from \[4(a - b - c)\],

So by subtracting we get,

\[

4(a - b - c) - 3(a + b) \\

= 4a - 4b - 4c - 3a - 3b \\

= a - 7b - 4c \\

\]

Now from the result we have to subtract \[9(a - 2b + bc)\],

Then we have,

\[

(a - 7b - 4c) - 9(a - 2b + bc) \\

= a - 7b - 4c - 9a + 18b - 9bc \\

= - 8a + 11b - 4c - 9bc \\

\]

So, we have the answer as, \[ - 8a + 11b - 4c - 9bc\] which is option (a).