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You can find the perimeter and area of the square, when at least one measure of the circle or the square is given.

For a square with side length S, the following formulas are used

Perimeter \[ = 4S\]

Area \[ = {S^2}\]

Diagonal \[ = S\sqrt 2 \]

For a circle write the radius r, the following formulas are used circumference \[ = 2\pi r\]

Area \[ = \pi {r^2}\]

Therefore,

As we know before the diameter of the circle is equal to the side length of the square.

The side length of the square \[ = 28\,cm\]

Area of a circle \[ = \pi {r^2}\]

To find the area first of all we find the radius of the circle.

\[d = 28\,cm\, = \]side length of the square

Where ‘d’ is diameter of the circle

\[r = \dfrac{d}{2} = \dfrac{{28}}{2} = 14\,cm\]

As we know that radius is half of the diameter

Now we have the value of ‘r’ that is 14 cm

Putting the value of r in the formula

Area of circle

\[ = \pi {r^2}\]

\[ = \pi \times {(14)^{2\,}}\,c{m^2}\]

\[ = 196\,\pi \,c{m^2}\]

Hence the area of the circle is \[196\,\pi \,c{m^2}\]

Area of the square \[ = {S^2}\]

\[S = 28\,cm\]

\[ = 28 \times 28\,c{m^2}\]

\[ = 784\,c{m^2}\]

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