Question

# Find the angular elevation (angle of elevation from the ground level) of the sunWhen the length of the shadow of a $30cm$ long pole is $10\sqrt 3 m$.

${\text{AB = }}$ pole ${\text{BC = }}$ shadow ,$\angle \theta =$ angle of elevation from the ground level.
In $\Delta ABC$,
$\tan c = \frac{p}{b} = \frac{{30}}{{10\sqrt 3 }} = \sqrt 3 = \tan {60^0}$
$\angle c = {60^0} = \angle \theta$ (from alternate interior angles)