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When the length of the shadow of a $30cm$ long pole is $10\sqrt 3 m$.

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Hint: When you get a question of height and distance the best way of solving is to draw a suitable diagram of the question. And then apply trigonometric ratio for further solution. The term angle of elevation denotes the angle from the horizontal upward to an object on the observer's line of sight would be above the horizontal.

Complete step-by-step answer:

${\text{AB = }}$ pole ${\text{BC = }}$ shadow ,$\angle \theta = $ angle of elevation from the ground level.

In $\Delta ABC$,

$\tan c = \frac{p}{b} = \frac{{30}}{{10\sqrt 3 }} = \sqrt 3 = \tan {60^0}$

$\angle c = {60^0} = \angle \theta $ (from alternate interior angles)

Note: Whenever you get a question of height and distance the key concept of solving is draw a diagram as given in question. You should have knowledge of angle of elevation and depression and further apply trigonometric ratio for further solution.

Complete step-by-step answer:

${\text{AB = }}$ pole ${\text{BC = }}$ shadow ,$\angle \theta = $ angle of elevation from the ground level.

In $\Delta ABC$,

$\tan c = \frac{p}{b} = \frac{{30}}{{10\sqrt 3 }} = \sqrt 3 = \tan {60^0}$

$\angle c = {60^0} = \angle \theta $ (from alternate interior angles)

Note: Whenever you get a question of height and distance the key concept of solving is draw a diagram as given in question. You should have knowledge of angle of elevation and depression and further apply trigonometric ratio for further solution.