Question

# Find a zero of the polynomial $p(x) = 3x + 1$a. $\dfrac{1}{3}$b. $\dfrac{{ - 1}}{3}$c. 3d. -3

In the given problem, we have, our polynomial, $p(x) = 3x + 1$
Thus we get, $3x + 1 = 0$
$\Rightarrow 3x = - 1$
$\Rightarrow x = \dfrac{{ - 1}}{3}$
So, a zero of the polynomial is $= \dfrac{{ - 1}}{3}$