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**Hint:**In the given question, price of bus ticket for one child is given, also price of bus ticket for one adult is given. We multiply the cost of a bus ticket of one child with \[3\] and price of one adult with \[4\] and then add them to get the total cost.

**Complete step-by-step answer:**The price of a ticket for one child is Rs. \[65\], so the price of tickets for \[3\] children will be given as \[65 \times 3 = 195\].

So the price of tickets only for children will be Rs. \[195\].

Now, the price of a bus ticket for a single adult is Rs. \[110\], so for finding the price of tickets for \[4\] adults, we can simply multiply it by \[4\], which gives us \[110 \times 4 = 440\].

Now, we have the price of tickets of \[3\] children and \[4\] adults as Rs. \[195\] and Rs. \[440\] respectively.

To find the total cost, we can simply add the two prices and get the total amount.

Thus, on adding we get \[195 + 440 = 635\].

**So, the total cost of tickets for \[3\] children and \[4\] adults comes out to be Rs. \[635\].**

**Note:**Another method of solving this question is assigning the variables to the price of a ticket of one child and one adult.

So, if we assume the price of ticket of one child as \[x\] and price of ticket of one adult as \[y\], it is given in the question that \[x = 65\] and \[y = 110\] which can be denoted as equation (1) and (2) respectively.

The required value is of \[3x + 4y\].

To find this, we multiply equation (1) with \[3\] and equation (2) with \[4\]and add them.

On multiplying we get, \[3x = 65\] and \[4y = 440\].

Now if we add the left hand sides we get \[3x + 4y\], which is asked in the question.

So the right hand sides after being added gives \[195 + 440 = 635\], which is the required answer.

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