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# Compute: $\dfrac{{({{10}^4} + 324)({{22}^4} + 324)({{34}^4} + 324)({{46}^4} + 324)({{58}^4} + 324)}}{{({4^4} + 324)({{16}^4} + 324)({{28}^4} + 324)({{40}^4} + 324)({{52}^4} + 324)}}$ Verified
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Hint: The question is in the form of exponential. It is in the form of $\left( {{{\left( {{a^2}} \right)}^2} + {b^2}} \right)$, The b term for each and every term is same. The value of a is different for other terms. The given terms are in the form of $({x^4} + 324)$, this can be written as $({(x + 3)^2} + 9)({(x - 3)^2} + 9)$, this formula is implemented to each term and then we are going to simplify.

Consider the term $({(x + 3)^2} + 9)({(x - 3)^2} + 9)$, on multiplying this we have
$\Rightarrow {(x + 3)^2}({(x - 3)^2} + 9) + 9({(x - 3)^2} + 9)$
Multiplying to each term we have
$\Rightarrow {(x + 3)^2}{(x - 3)^2} + 9{(x + 3)^2} + 9{(x - 3)^2} + 81$
On simplifying we have
$\Rightarrow {({x^2} - 9)^2} + 9(2{x^2} + 18) + 81$
Expanding the terms
$\Rightarrow {x^4} + 81 - 18{x^2} + 18{x^2} + 162 + 81$
On further simplification we have
$\Rightarrow {x^4} + 324$
Therefore $({x^4} + 324) = ({(x - 3)^2} + 9)({(x + 3)^2} + 9)$----------- (1)
Now consider the given question
$\Rightarrow \dfrac{{({{10}^4} + 324)({{22}^4} + 324)({{34}^4} + 324)({{46}^4} + 324)({{58}^4} + 324)}}{{({4^4} + 324)({{16}^4} + 324)({{28}^4} + 324)({{40}^4} + 324)({{52}^4} + 324)}}$
By using the equation (1) the above inequality is written as
$\Rightarrow \dfrac{{({7^2} + 9)({{13}^2} + 9)({{19}^2} + 9)({{25}^2} + 9)({{31}^2} + 9)({{37}^2} + 9)({{43}^2} + 9)({{49}^2} + 9)({{55}^2} + 9)({{61}^2} + 9)}}{{({1^2} + 9)({7^2} + 9)({{13}^2} + 9)({{19}^2} + 9)({{25}^2} + 9)({{31}^2} + 9)({{37}^2} + 9)({{43}^2} + 9)({{49}^2} + 9)({{55}^2} + 9)}}$
When we see both the numerator and the denominator there are so many common terms hence we can cancel them.
On cancelling them we have
$\Rightarrow \dfrac{{({{61}^2} + 9)}}{{({1^2} + 9)}}$
Now we have a very simplified term, in the numerator there is only one term and in the denominator also we can see only one term.
The terms which are in the form of exponents. On expanding it we have
$\Rightarrow \dfrac{{(61 \times 61 + 9)}}{{(1 \times 1 + 9)}}$
Now multiply 61 and 61 in the numerator. Multiply 1 and 1 in the denominator.
$\Rightarrow \dfrac{{(3721 + 9)}}{{(1 + 9)}}$
Now add 3721 and 9 in the numerator. Add 1 and 9 in the denominator.
$\Rightarrow \dfrac{{3730}}{{10}}$
On dividing the 3730 by 10
$\Rightarrow 373$
Hence we have simplified the given inequality.

Note: The number can be written in the form of the exponents and the exponent number can also be written in the form of the usual number. We must know about the law of exponents. Since the given terms are exponential, we need a law of exponents to solve.