Courses
Courses for Kids
Free study material
Offline Centres
More
Store

# Can someone please explain step by step how to balance ${\text{Ca}} + {{\text{N}}_{\text{2}}} \to {\text{C}}{{\text{a}}_{\text{3}}}{{\text{N}}_{\text{2}}}$

Last updated date: 20th Jun 2024
Total views: 374.1k
Views today: 10.74k
Verified
374.1k+ views
Hint: We know that a chemical is called a balanced chemical equation when the number of atoms of all elements is equal in both the product and reactant side of the reaction. While balancing a chemical equation we also need to equate charges if any charge is present.

In balancing a chemical equation, we have to equate the number of atoms of all elements in
both sides (product side and reactant side) of the reaction.
The given equation is,
${\text{Ca}} + {{\text{N}}_{\text{2}}} \to {\text{C}}{{\text{a}}_{\text{3}}}{{\text{N}}_{\text{2}}}$
Here, there is one calcium atom at the reactant side and three calcium atoms at the product side. So, the equation is not balanced.
To balance the number of calcium atoms, we have to add coefficient 3 to the Ca at the reactant side. Now, the equation becomes,
${\text{3Ca}} + {{\text{N}}_{\text{2}}} \to {\text{C}}{{\text{a}}_{\text{3}}}{{\text{N}}_{\text{2}}}$
Now, the number of calcium atoms in both sides of the reaction is 3 and the number of nitrogen atoms is 2. So, the equation is balanced.

Hence, the balanced equation is ${\text{3Ca}} + {{\text{N}}_{\text{2}}} \to {\text{C}}{{\text{a}}_{\text{3}}}{{\text{N}}_{\text{2}}}$.