Question

Bond Order of BN is:

Answer 1

Hint: In order to find the bond order, count the number of total electrons present in the compound and use molecular orbital theory. Use the Bond Order formula finally to get the answer.

Complete step by step answer:
The compound given to us in the question has the chemical name Boron Nitride.
Bond order is defined as, “half of the difference between the number of electrons in Bonding Molecular orbitals and Antibonding Molecular Orbitals.” It indicates the number of bonds in the compound.
Number of electrons in Boron Nitride
= electrons in boron + electrons in nitrogen
= 5 + 7 = 12.
Now, let us write the electronic configuration of BN according to Molecular Orbital Theory –
\[\left( \text{ }\!\!\sigma\!\!\text{ 1}{{\text{s}}^{\text{2}}}\text{ }\!\!\sigma\!\!\text{ *1}{{\text{s}}^{\text{2}}} \right)\text{ }\left( \text{ }\!\!\sigma\!\!\text{ 2}{{\text{s}}^{\text{2}}}\text{ }\!\!\sigma\!\!\text{ *2}{{\text{s}}^{\text{2}}} \right)\text{ }\left( \text{ }\!\!\pi\!\!\text{ 2}{{\text{p}}_{\text{x}}}^{\text{2}}\text{= }\!\!\pi\!\!\text{ 2}{{\text{p}}_{\text{y}}}^{\text{2}} \right)\text{ }\!\!~\!\!\text{ }\!\!~\!\!\text{ }\]
where, σ and π indicate bonding molecular orbitals
     σ* and π* indicate antibonding molecular orbitals.
As we can see, the number of Bonding electrons = 8
And, the number of Antibonding electrons = 4
As we know,
Bond Order = (Number of Bonding electrons – Number of Antibonding electrons) / 2
Therefore, Bond Order of BN = \[\dfrac{8-4}{2}\] = 2.
Therefore, the answer is – The Bond Order of BN is 2.

Note: A bond order equal to zero indicates that no bond exists, i.e. the compound doesn’t exist. The stability of compounds increases with increasing Bond order.