Question

How many atoms of each element are in the chemical formula \[Ca{(OH)_2}\] ?

Answer 1

Hint: We know that 1 mole of the substance is the basic unit which used to express the amount of substance. The 1 mole of substance contains the same amount of substance which is present in 12g of carbon-12 atom. The 1 mole of substance contains \[6.023 \times {10^{23}}\]of elementary entities.

Complete step by step solution:
So to solve this question first we need to calculate the number of atoms which are present in one mole of the calcium hydroxide compound and then multiply each element atoms by the Avogadro number.
So in the one mole of the compound of calcium hydroxide is made up three types of elements that are calcium, hydrogen, and oxygen. Each atom of the calcium hydroxide has \[6.023 \times {10^{23}}\] atoms per mole.
So the number of atom of oxygen in the calcium hydroxide is = 2
The number of atom of hydrogen in the calcium hydroxide is = 2
The number of atom of calcium in the calcium hydroxide is = 1
So the total number of atoms in calcium hydroxide is= 2+2+1=5
The oxygen atoms in a mole of calcium hydroxide is = \[2 \times 6.023 \times {10^{23}} = 12.046 \times {10^{23}}\]
The hydrogen atoms in a mole of calcium hydroxide is= \[2 \times 6.023 \times {10^{23}} = 12.046 \times {10^{23}}\]
The calcium atoms in a mole of calcium hydroxide is= \[6.023 \times {10^{23}}\]
So the 1 mole of calcium hydroxide contains \[6.023 \times {10^{23}}\]atoms of calcium, \[12.046 \times {10^{23}}\] atoms of oxygen and \[12.046 \times {10^{23}}\] atoms of hydrogen.

Note: Calcium hydroxide is the slaked lime which is white powdery in appearance. It is not very soluble in water and it is a hexagonal crystal in structure. It is soluble slightly in acids and glycerol. It is used in the paper industry and in the process of sewage treatment.