Answer

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**Hint:**As per the problem monthly salary of Sanjay is less than Aditya’s salary. So, if the salary of A is \[a\% \] more than the salary of B then B’s salary will be \[\dfrac{{100}}{{100 + a}}\] of A’s salary. With the help of the formula we will find the monthly salary of Sanjay. With the monthly salary found we will multiply 12 to get the required annual salary.

**Complete step-by-step answer:**

It is given that; Aditya’s monthly salary is \[15\% \] more than Sanjay’s monthly salary.

Aditya’s monthly salary is Rs. \[17250\].

We have to find Sanjay's monthly salary.

Let us consider, the monthly salary of Sanjay is \[x\].

Since, Aditya’s salary is \[15\% \] more than Sanjay’s monthly salary.

So, the salary of Aditya is \[x + x \times 15\% \]

Let us simplify the above salary of Aditya using the percentage formula, we get,

Aditya’s salary is \[\dfrac{{115x}}{{100}}\]

According to the problem it is given that Aditya’s salary is Rs. \[17250\]

i.e. \[\dfrac{{115x}}{{100}} = 17250\]

Let us solve the above equation to get x, which is the salary of Sanjay we get,

\[x = 17250 \times \dfrac{{100}}{{115}} = 15000\]

Hence we have found that the monthly salary for Sanjay is Rs.\[15000.\]

We should calculate the annual salary of Sanjay for that we have to multiply his monthly salary with 12.

The monthly salary of Sanjay is \(15000 \times 12 = 180000\)

Hence the annual salary of Sanjay is \(Rs180000\)

**Note:**The problem can be solved by another process. We can solve it directly.

As Aditya’s monthly salary is \[15\% \] more than Sanjay’s monthly salary and Aditya’s monthly salary is Rs. \[17250\].

So, Sanjay’s salary will be \[17250 \times \dfrac{{100}}{{115}}\]

On solving the equation which is given in the above equation, we get, the monthly salary of Sanjay as \[ = Rs.15000\]

Hence, monthly salary for Sanjay is Rs. \[15000.\]

Here percentage conversion plays a major role that is \(x\% = x \times 100\% \)

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