
Acceleration is defined as the rate of change of velocity. Unit of rate of change of acceleration is:
$\left( A \right)\dfrac{m}{{{s^2}}}$
$\left( B \right)\dfrac{m}{{{s^3}}}$
$\left( C \right)\dfrac{m}{s}$
$\left( D \right)\dfrac{{{m^2}}}{{{s^2}}}$
Answer
591.6k+ views
Hint: In this question use the property that velocity is the ratio of distance to time and distance is measured in meter and time is measured in seconds later on in the solution use the property that rate of change of velocity is nothing but the differentiation of velocity w.r.t time so use these concepts to reach the solution of the question.
Complete step-by-step solution:
As we know that the velocity (V) is the ratio of distance (d) to time (t).
$ \Rightarrow V = \dfrac{d}{t}$
Now we all know that the unit of distance is meter and unit of time is sec.
So the unit of velocity (V) is m/s.
Now acceleration is known as rate of change of velocity.
As we see velocity is changing w.r.t. time so acceleration is also changing w.r.t. time.
Therefore acceleration (a) is the rate of change of velocity w.r.t. time (i.e. differentiation of the velocity w.r.t time)
$ \Rightarrow a = \dfrac{{dv}}{{dt}}$
So the unit of acceleration is $\dfrac{{\dfrac{m}{s}}}{s} = \dfrac{m}{{{s^2}}}$
Now we have to find out the unit of the rate of change of acceleration.
So rate of change of acceleration w.r.t time (I.e. differentiation of acceleration) is given as
$ \Rightarrow \dfrac{{da}}{{dt}}$
So the unit of rate of change of acceleration is $ = \dfrac{{{\text{unit of acceleration}}}}{{{\text{unit of time}}}} = \dfrac{{\dfrac{m}{{{s^2}}}}}{s} = \dfrac{m}{{{s^3}}}$
So this is the required answer.
Hence option (B) is the correct answer.
Note – Whenever we face such types of questions the key concept we have to remember is to always recall the unit of velocity and time so acceleration is the rate of change of velocity w.r.t. time we can easily calculate the unit of acceleration then use this unit to calculate the unit of rate of change of acceleration as above and simplify, we will get the required answer.
Complete step-by-step solution:
As we know that the velocity (V) is the ratio of distance (d) to time (t).
$ \Rightarrow V = \dfrac{d}{t}$
Now we all know that the unit of distance is meter and unit of time is sec.
So the unit of velocity (V) is m/s.
Now acceleration is known as rate of change of velocity.
As we see velocity is changing w.r.t. time so acceleration is also changing w.r.t. time.
Therefore acceleration (a) is the rate of change of velocity w.r.t. time (i.e. differentiation of the velocity w.r.t time)
$ \Rightarrow a = \dfrac{{dv}}{{dt}}$
So the unit of acceleration is $\dfrac{{\dfrac{m}{s}}}{s} = \dfrac{m}{{{s^2}}}$
Now we have to find out the unit of the rate of change of acceleration.
So rate of change of acceleration w.r.t time (I.e. differentiation of acceleration) is given as
$ \Rightarrow \dfrac{{da}}{{dt}}$
So the unit of rate of change of acceleration is $ = \dfrac{{{\text{unit of acceleration}}}}{{{\text{unit of time}}}} = \dfrac{{\dfrac{m}{{{s^2}}}}}{s} = \dfrac{m}{{{s^3}}}$
So this is the required answer.
Hence option (B) is the correct answer.
Note – Whenever we face such types of questions the key concept we have to remember is to always recall the unit of velocity and time so acceleration is the rate of change of velocity w.r.t. time we can easily calculate the unit of acceleration then use this unit to calculate the unit of rate of change of acceleration as above and simplify, we will get the required answer.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

Which animal has three hearts class 11 biology CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

