
Aasheesh can paint his doll in $20$ minutes and his sister chinki can do so in $25$ minutes. They paint the doll together for five minutes. At this junctions they have a quarrel and chinki with draws from painting.In how many minutes will aasheesh finish the painting of the remaining doll?
Answer
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Hint: A fraction speaks to a piece of an entire or, all the more by and large, quite a few equivalent parts. At the point when spoken in ordinary English, a portion portrays the number of parts of a specific size there are, for instance, one-half, eight-fifths, seventy five percent.
Complete step by step answer:
Aasheesh can paint a doll in $20$ minutes, chinki can do the same in $25$ minutes.
work done by Aasheesh in $1$ minute $ = \dfrac{1}{{20}}$
Work done by Chinki in $1$ minute $ = \dfrac{1}{{25}}$
Work done by them together$ = \dfrac{1}{{20}} + \dfrac{1}{{25}}$
$ \Rightarrow \dfrac{{5 + 4}}{{100}} = \dfrac{9}{{100}}$
Work done by them in $5$ minute $ \Rightarrow 5 \times \dfrac{9}{{100}} = \dfrac{9}{{20}}$
Remaining , work $ \Rightarrow 1 - \dfrac{9}{{20}} = \dfrac{{11}}{{20}}$
It is given that the remaining work is done by Aaasheen.
The work done by Aasheesh in $20$ minutes.
$\therefore \dfrac{{11}}{{20}}th$ work will be done by Aasheesh in $(20 \times \dfrac{{11}}{{20}})$ minutes or $11$ minutes
Thus, the remaining work is done by Aasheesh in $11$ minutes.
Note:any of different numerical tasks that are comparable to somehow or another to augmentation of the genuine numbers yet are characterized for other or bigger arrangements of components, (for example, complex numbers, vectors, grids, or capacities). A numerical activity that is at its least difficult is a curtailed cycle of adding a whole number to zero a predetermined number of times and that is reached out to different numbers as per laws that are substantial for numbers.
Complete step by step answer:
Aasheesh can paint a doll in $20$ minutes, chinki can do the same in $25$ minutes.
work done by Aasheesh in $1$ minute $ = \dfrac{1}{{20}}$
Work done by Chinki in $1$ minute $ = \dfrac{1}{{25}}$
Work done by them together$ = \dfrac{1}{{20}} + \dfrac{1}{{25}}$
$ \Rightarrow \dfrac{{5 + 4}}{{100}} = \dfrac{9}{{100}}$
Work done by them in $5$ minute $ \Rightarrow 5 \times \dfrac{9}{{100}} = \dfrac{9}{{20}}$
Remaining , work $ \Rightarrow 1 - \dfrac{9}{{20}} = \dfrac{{11}}{{20}}$
It is given that the remaining work is done by Aaasheen.
The work done by Aasheesh in $20$ minutes.
$\therefore \dfrac{{11}}{{20}}th$ work will be done by Aasheesh in $(20 \times \dfrac{{11}}{{20}})$ minutes or $11$ minutes
Thus, the remaining work is done by Aasheesh in $11$ minutes.
Note:any of different numerical tasks that are comparable to somehow or another to augmentation of the genuine numbers yet are characterized for other or bigger arrangements of components, (for example, complex numbers, vectors, grids, or capacities). A numerical activity that is at its least difficult is a curtailed cycle of adding a whole number to zero a predetermined number of times and that is reached out to different numbers as per laws that are substantial for numbers.
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