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The volume of the rectangular cuboid of wax is $v = lbh$, where l is the length, b is the breadth and h is the height.

$

\Rightarrow v = 66 \times 42 \times 21 \\

\Rightarrow v = 58212c{m^3} \\

$

Therefore, the volume of the solid wax is $58212c{m^3}$

Now, The volume of the cylindrical shape candles is, say V’ is given as $V' = \pi {r^2}h$, where r is the radius and h is the height.

In question, it is given that diameter is 4.2cm and height is 2.8cm.

Since we know $radius = \dfrac{{diameter}}{2} = \dfrac{{4.2}}{2} = 2.1cm$

$

\Rightarrow v' = \pi \times {(2.1)^2} \times 2.8 \\

\Rightarrow v' = 38.808c{m^3} \\

$

Let the number of candles be $n$

Therefore, considering the fact that the Volume of the rectangular solid wax is the same as the total volume of cylindrical candles.

$

\Rightarrow v = v' \times n \\

\Rightarrow n = \dfrac{v}{{v'}} \\

\Rightarrow n = \dfrac{{58212}}{{38.808}} = 1500 \\

$

Therefore, The number of candles is 1500.