Answer
424.2k+ views
Hint: In basic type of question related to speed, distance and time we have one moving object but when we have two objects and out of them one is for sure moving and the second one is either static or moving and when they are moving either in the same direction or in the opposite direction they will cross each other. Then there comes the concept of relative speed. Relative speed in the case of the opposite direction of movement is added up but in the case of same direction movement it becomes the difference of the two.
Complete step by step solution: If two object bodies are moving in opposite direction at $u$ kmph and $v$ kmph, where$u > v$,
then their relative speed is $ = (u + v)$ kmph
Here in our question we have a train and a man as two object bodies.
Therefore on comparing from the above statement the given information can be written as
$u = 60$ kmph, $v = 6$ kmph.
The length of the train, say $l$ =$110$ m
We know the formula for time $t$ taken by a moving object when speed is $s$ and the distance has to be covered is $d$ is $t = \dfrac{d}{s}$.
Now the time taken by the train to cross the man $t = \dfrac{l}{{u + v}}$
Therefore by substituting the values, we have
$t = \dfrac{{110}}{{60 + 6}} = \dfrac{{110}}{{66}} = \dfrac{5}{3} = 1\dfrac{2}{3}h$
So the required time is in mixed fraction form. The fraction part of mixed fraction is in hour and can be converted into minutes.
Hence time required by a train to pass the man running in the opposite direction is 1 hour and40 minutes.
Note: 1. If two object bodies are moving in the same direction at $u$kmph and $v$ kmph, where $u > v$, then their relative speed is = $(u - v)$ kmph.
2. If both the object bodies have remarkable length then the distance has to be covered becomes $d + l_1 + l_2$ where $d$ is the distance between them, $l_1$ is the length of one object and $l_2$ is length of the second object.
Complete step by step solution: If two object bodies are moving in opposite direction at $u$ kmph and $v$ kmph, where$u > v$,
then their relative speed is $ = (u + v)$ kmph
Here in our question we have a train and a man as two object bodies.
Therefore on comparing from the above statement the given information can be written as
$u = 60$ kmph, $v = 6$ kmph.
The length of the train, say $l$ =$110$ m
We know the formula for time $t$ taken by a moving object when speed is $s$ and the distance has to be covered is $d$ is $t = \dfrac{d}{s}$.
Now the time taken by the train to cross the man $t = \dfrac{l}{{u + v}}$
Therefore by substituting the values, we have
$t = \dfrac{{110}}{{60 + 6}} = \dfrac{{110}}{{66}} = \dfrac{5}{3} = 1\dfrac{2}{3}h$
So the required time is in mixed fraction form. The fraction part of mixed fraction is in hour and can be converted into minutes.
Hence time required by a train to pass the man running in the opposite direction is 1 hour and40 minutes.
Note: 1. If two object bodies are moving in the same direction at $u$kmph and $v$ kmph, where $u > v$, then their relative speed is = $(u - v)$ kmph.
2. If both the object bodies have remarkable length then the distance has to be covered becomes $d + l_1 + l_2$ where $d$ is the distance between them, $l_1$ is the length of one object and $l_2$ is length of the second object.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)