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**Hint:**You are given the length and breadth of a table and you are asked to find the perimeter of that table-top which is given by $2\left( {length + breadth} \right)$. Using this you will be able to get the answer.

**Complete step-by-step answer:**

Now it is given that the table-top measures $2m25cm$ by $1m50cm$. This means that the length of the table is $2m25cm$ and breadth is $1m50cm$.

Here $ABCD$ is a table and $PCBQ$ is the table-top whose measurement is given by $2m25cm$ by $1m50cm$.

This means that the length of the table $PQ$$ = $ $2m25cm$ and breadth $BP$$ = $ $1m50cm$ and it is in the form of the rectangle.

Now the length is given in the form $x$ $m$$ and $ $y$$cm$ now we need to convert it into either $meter$ or $centimeter$. So if we try to convert $x$ $m$ $and$ $y$$cm$ into $centimeter$ then it will become:

$\left( {\left( {x \times 100} \right) + y} \right)cm$.

So here $PQ$ is given as $2m25cm$, we have to change it into $cm$.

$PQ = \left( {\left( {2 \times 100} \right) + 25} \right)cm$

$ = 225cm$

Similarly we have to change $BP$$ = $$1m50cm$

$ = \left( {\left( {1 \times 100} \right) + 50} \right)cm$

$ = 150cm$

Now it is asked to find out the perimeter of the table-top which is $BPQC$.

Hence we know that $BPQC$ is a rectangle and we know that the perimeter of the rectangle is equal to $2\left( {length + breadth} \right)$. Here adjacent sides are calculated as

$PQ$$ = 225cm$

$BP = 150cm$

Perimeter of the table top $ = $ $2\left( {PQ + BP} \right)$

$ = $$2\left( {225 + 150} \right)$$cm$

$ = $ $2\left( {375} \right)cm$

$ = 750cm$

Now we have perimeter $ = 750cm$

We can write it as $ = \left( {\left( {7 \times 100} \right) + 50} \right)cm$

Which means it is $7m50cm$.

**Note:**To convert $x$ $m$ $y$ $cm$ into $cm$, we have to use $\left( {100x + y} \right)cm$. We should know that the perimeter of the rectangle is equal to $2\left( {length + breadth} \right)$.

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