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When we clearly look at the question, they mentioned that the bacteria when it is enlarged for \[50,000\] times it attains the length of $5cm$.

So, if we want to find out the actual length of the bacteria then we should divide the length obtained value with the how many times the bacteria are enlarged.

In simple words, it gives the length of the bacteria when the photograph is enlarged for unity it means no enlargement at all.

So, from the data we can obtain that the length of bacteria after enlargement is $5cm$ and enlarged \[50,000\] times. Substituting these values, we get as follows:

Actual length of the bacteria $ = \dfrac{5}{{50000}}$

$

= \dfrac{1}{{10000}} \\

= {10^{ - 4}}cm \\

$

As per now, we got the actual length of the bacteria and that is ${10^{ - 4}}cm$.

Now we can able to calculate the length of bacteria for any amount of enlargement value by simply multiplying with the unity value that we obtained recently.

In the second part of the question, we are asked to find out the length of the bacteria if the photograph is enlarged for the $20,000$ times.

So, just multiply this enlargement value with the actual length of the bacteria.

We get as follows:

When the photograph of a bacteria is enlarged $20,000$ times attains a length $ = 20000 \times {10^{ - 4}}= 2cm$

So, the bacterial will be visible with $2cm$ length when it is enlarged for the $20,000$ times.