
A person sold an article for Rs.230 and incurred a loss of 8%. What should be the selling price in order to earn a profit of 8%?
Answer
581.1k+ views
Hint: In this question, we will first calculate the actual cost price of the article, since it is being sold at a loss so, C.P would be more than Rs. 230 and then with that Cost price we will find out the new selling price with profit of 8% which is the required answer.
Complete step-by-step answer:
It is given that the selling price (S.P) of the article = Rs. 230
Loss incurred on the article is 8 %;
Now, we will find the cost price of the article using the following formula:
$$C.P = \dfrac{{100}}{{100 - loss\% }} \times S.P$$
= $$\dfrac{{100}}{{100 - 8}} \times 230$$
On solving, we get
=$$\dfrac{{100}}{{92}} \times 230$$= $$250$$
Hence, the cost price of that article was Rs. 250.
Now, we will find the new selling price of the article so that the person will get the profit of 8% this time.
Using the formula:
$$S.P = \dfrac{{100 + profit\% }}{{100}} \times C.P$$
We will put all the values in the above formula and we will get;
$$S.P = \dfrac{{100 + 8}}{{100}} \times 250$$
On solving the above equation, we get;
$$S.P = \dfrac{{108}}{{100}} \times 250$$
$$\eqalign{
& S.P = \dfrac{{108}}{{10}} \times 25 = \dfrac{{108}}{2} \times 5 \cr
& = 54 \times 5 \cr
& = 270 \cr
& \cr} $$
Hence, we get the selling price of the article as Rs. 270, when the person incurred the profit of 8%.
Note:We will find out the original cost price of the article as loss % of 8% is given, now if we want to sell that article on profit of 8%, we will calculate the new selling price using the formula of profit %.Students should remember the formulas i.e $$C.P = \dfrac{{100}}{{100 - loss\% }} \times S.P$$ and $$S.P = \dfrac{{100 + profit\% }}{{100}} \times C.P$$ for solving these types of problems.
Complete step-by-step answer:
It is given that the selling price (S.P) of the article = Rs. 230
Loss incurred on the article is 8 %;
Now, we will find the cost price of the article using the following formula:
$$C.P = \dfrac{{100}}{{100 - loss\% }} \times S.P$$
= $$\dfrac{{100}}{{100 - 8}} \times 230$$
On solving, we get
=$$\dfrac{{100}}{{92}} \times 230$$= $$250$$
Hence, the cost price of that article was Rs. 250.
Now, we will find the new selling price of the article so that the person will get the profit of 8% this time.
Using the formula:
$$S.P = \dfrac{{100 + profit\% }}{{100}} \times C.P$$
We will put all the values in the above formula and we will get;
$$S.P = \dfrac{{100 + 8}}{{100}} \times 250$$
On solving the above equation, we get;
$$S.P = \dfrac{{108}}{{100}} \times 250$$
$$\eqalign{
& S.P = \dfrac{{108}}{{10}} \times 25 = \dfrac{{108}}{2} \times 5 \cr
& = 54 \times 5 \cr
& = 270 \cr
& \cr} $$
Hence, we get the selling price of the article as Rs. 270, when the person incurred the profit of 8%.
Note:We will find out the original cost price of the article as loss % of 8% is given, now if we want to sell that article on profit of 8%, we will calculate the new selling price using the formula of profit %.Students should remember the formulas i.e $$C.P = \dfrac{{100}}{{100 - loss\% }} \times S.P$$ and $$S.P = \dfrac{{100 + profit\% }}{{100}} \times C.P$$ for solving these types of problems.
Recently Updated Pages
Two men on either side of the cliff 90m height observe class 10 maths CBSE

What happens to glucose which enters nephron along class 10 biology CBSE

Cutting of the Chinese melon means A The business and class 10 social science CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

Show an aquatic food chain using the following organisms class 10 biology CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

Trending doubts
Differentiate between Food chain and Food web class 10 biology CBSE

What is UltraEdge (Snickometer) used for in cricket?

What are the public facilities provided by the government? Also explain each facility

On the outline map of India mark the following appropriately class 10 social science. CBSE

Why does India have a monsoon type of climate class 10 social science CBSE

A sum of 10000 is invested at the rate of 8 per year class 10 maths CBSE

