
A parallel plate capacitor is charged and then isolated. What is the effect of increasing the plate separation on charge, potential, capacitance, respectively?
(A) Constant, decreases, decreases
(B) Increases, decreases, decreases
(C) Constant, decreases, increases
(D) Constant. Increases, decreases
Answer
542.4k+ views
Hint:Capacitance in general is defined as the ratio of the charge on the plates of the conductor to the potential difference. We can find the effect of increase in the plate separation on charge(Q), potential(V) and capacitance(C). The capacitance of a capacitor depends upon a number of factors but the most important is what type of capacitor it is whether a parallel plate capacitor or cylindrical capacitor.
Formula Used:
Capacitance for a parallel plate capacitor is given as $C=\dfrac{{{\varepsilon }_{0}}A}{d}$,
where A is area of cross section, d is the distance between two plates and ${{\varepsilon }_{0}}$is the relative permittivity.
Complete answer:
Capacitance(C) is defined as the ratio of the charge stored in the conductor to the potential difference(V), $C=Q/V$. Charge on the plates is, $Q=CV$. And the potential between the plates is $V=Q/C$. For a parallel plate capacitor the capacitance is equal to $C=\dfrac{{{\varepsilon }_{0}}A}{d}$, where A is area of cross section, d is the distance between two plates and ${{\varepsilon }_{0}}$ is the relative permittivity.
Therefore with an increase in the separation between the plates (d), capacitance increases as it is inversely related to distance between plates of capacitor and potential decreases as it is inversely proportional to capacitance. Due to the increase in capacitance and decreases in potential by the same factor, the charge remains constant.
Note:One should know the formula for capacitance for a parallel plate capacitor to solve such types of problems. A cylindrical capacitor consists of a hollow or a solid cylindrical conductor surrounded by another concentric hollow spherical cylinder. When the capacitor is connected to a battery then the charging process gets started. The charge moves from one plate of the capacitor to the other and so an electric field is produced in the space between the two plates.
Formula Used:
Capacitance for a parallel plate capacitor is given as $C=\dfrac{{{\varepsilon }_{0}}A}{d}$,
where A is area of cross section, d is the distance between two plates and ${{\varepsilon }_{0}}$is the relative permittivity.
Complete answer:
Capacitance(C) is defined as the ratio of the charge stored in the conductor to the potential difference(V), $C=Q/V$. Charge on the plates is, $Q=CV$. And the potential between the plates is $V=Q/C$. For a parallel plate capacitor the capacitance is equal to $C=\dfrac{{{\varepsilon }_{0}}A}{d}$, where A is area of cross section, d is the distance between two plates and ${{\varepsilon }_{0}}$ is the relative permittivity.
Therefore with an increase in the separation between the plates (d), capacitance increases as it is inversely related to distance between plates of capacitor and potential decreases as it is inversely proportional to capacitance. Due to the increase in capacitance and decreases in potential by the same factor, the charge remains constant.
Note:One should know the formula for capacitance for a parallel plate capacitor to solve such types of problems. A cylindrical capacitor consists of a hollow or a solid cylindrical conductor surrounded by another concentric hollow spherical cylinder. When the capacitor is connected to a battery then the charging process gets started. The charge moves from one plate of the capacitor to the other and so an electric field is produced in the space between the two plates.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
The pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSE

Which prominent US inventor was known as the Wizard class 12 social science CBSE

Which state in India is known as the Granary of India class 12 social science CBSE

Give simple chemical tests to distinguish between the class 12 chemistry CBSE

What is virtual and erect image ?

Explain the energy losses in the transformer How are class 12 physics CBSE

