Answer
453.3k+ views
Hint: The given question uses the concepts of probability and divisibility. Recall the formula for finding the probability of choosing $x$ items from a group of $y$ items , where $x\le y$. Also, recall the test of divisibility by $8$.
Before proceeding with the solution , first, we should know about probability and divisibility.
Probability is defined as the likeness of an event to occur. Mathematically , it is defined as the ratio of number of favorable outcomes to the number of possible outcomes.
Divisibility rules are a quick way to determine whether large numbers are divisible by a given number.
Now , the divisibility rule for a number to be divisible by $8$ is “ if the last three digits of a number are divisible by $8$ , then the number is divisible by $8$ .”
We know, the numbers between $1$ and $100$ are two-digit numbers. So, we cannot apply the divisibility rule to test whether a number is divisible by $8$ or not. So, we have to pick numbers by adding $8$ to every multiple of $8$ . The first multiple is $8$ . The next will be $8+8=16$ . Similarly, the other numbers divisible by $8$ are $24,32,40,48,56,64,72,80,88$ and $96$ . So, the total number of numbers between $1$ and $100$ that are divisible by $8$ is $12$ .
Now, to find the value of $m$ , we first need to find the probability of choosing a number divisible by $8$ from a set of numbers between $1$ and $100$ .
The favorable event is choosing a number between $1$ and $100$ which is divisible by $8$.
So , the number of favorable outcomes is $12$.
The total possible outcome is choosing any number between $1$ and $100$. So , the number of possible outcomes is $100$ .
So , probability $P=\dfrac{12}{100}=\dfrac{3}{25}$.
Now , in the question , the value of the probability is given as $\dfrac{m}{25}$ .
So, $\dfrac{m}{25}=\dfrac{3}{25}$ .
Or, $m=3$ .
Hence, the value of $m$ is equal to $3$.
Note: To find the number of numbers between $1$ and $100$ that are divisible by $8$ , we can divide $100$ by $8$ , and the quotient will be our required value , i.e. $\dfrac{100}{8}=12(rem=4)$. So, the number of numbers between $1$ and $100$ that are divisible by $8$ is $12$.
Before proceeding with the solution , first, we should know about probability and divisibility.
Probability is defined as the likeness of an event to occur. Mathematically , it is defined as the ratio of number of favorable outcomes to the number of possible outcomes.
Divisibility rules are a quick way to determine whether large numbers are divisible by a given number.
Now , the divisibility rule for a number to be divisible by $8$ is “ if the last three digits of a number are divisible by $8$ , then the number is divisible by $8$ .”
We know, the numbers between $1$ and $100$ are two-digit numbers. So, we cannot apply the divisibility rule to test whether a number is divisible by $8$ or not. So, we have to pick numbers by adding $8$ to every multiple of $8$ . The first multiple is $8$ . The next will be $8+8=16$ . Similarly, the other numbers divisible by $8$ are $24,32,40,48,56,64,72,80,88$ and $96$ . So, the total number of numbers between $1$ and $100$ that are divisible by $8$ is $12$ .
Now, to find the value of $m$ , we first need to find the probability of choosing a number divisible by $8$ from a set of numbers between $1$ and $100$ .
The favorable event is choosing a number between $1$ and $100$ which is divisible by $8$.
So , the number of favorable outcomes is $12$.
The total possible outcome is choosing any number between $1$ and $100$. So , the number of possible outcomes is $100$ .
So , probability $P=\dfrac{12}{100}=\dfrac{3}{25}$.
Now , in the question , the value of the probability is given as $\dfrac{m}{25}$ .
So, $\dfrac{m}{25}=\dfrac{3}{25}$ .
Or, $m=3$ .
Hence, the value of $m$ is equal to $3$.
Note: To find the number of numbers between $1$ and $100$ that are divisible by $8$ , we can divide $100$ by $8$ , and the quotient will be our required value , i.e. $\dfrac{100}{8}=12(rem=4)$. So, the number of numbers between $1$ and $100$ that are divisible by $8$ is $12$.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)